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3 years ago

The polynomial x3+8 is equal to

Mathematics

2 answers:

aev [14]3 years ago

4 0

Answer:

Polynomial (x + 2) (x² − 2x + 4 ).

Step-by-step explanation:

Given : x³+ 2³.

To find : Solve .

Solution : We have given that x³+ 2³.

By the cubic formula : a³ + b³ = (a + b) (a² − ab + b² ).

Then

x³+ 2³ = (x + 2) (x² − 2x + 2² ).

x³+ 2³ = (x + 2) (x² − 2x + 4 ).

Therefore, Polynomial (x + 2) (x² − 2x + 4 ).

s344n2d4d5 [400]3 years ago

3 0

The polynomial x3+8 is equal to (x+2)(x2-2x+4)

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Solve y= -2x + 9 y= 4x -3

wlad13 [49]

y = -2x + 9

y = 4x - 3

y is isolated in both equations, thus you may set the expressions (-2x + 9) and (4x - 3) equal to each other and solve for x.

-2x + 9 = 4x - 3

Subtract 9 from both sides.

-2x + 9 - 9 = 4x - 3 - 9

-2x = 4x - 12

Subtract 4x from both sides.

-2x - 4x = 4x - 12 - 4x

-6x = -12

Divide both sides by -6.

-6x/-6 = -12/-6

x = 2

Substitute 2 for x into one of the original equations to find y.

y = 4x - 3 (given)

y = 4(2) - 3 (substitute)

y = 8 - 3 (multiply)

y = 5 (subtract)

Plug x- and y-values into original equations to check work.

5 = -2(2) + 9

5 = - 4 + 9

5 = 5

5 = 4(2) - 3

5 = 8 - 3

5 = 5

Answer:

x = 2 and y = 5; (2, 5).

5 0

3 years ago

Read 2 more answers

4/5 of a number is 32

andrew11 [14]

Answer:

x = 40

Step-by-step explanation:

Step 1: Write out an equation

4/5(x) = 32

Step 2: Solve by dividing both sides by 4/5

x = 32/(4/5)

Use KCF (Keep Change Flip) if you do not have a calc.

x = 40

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3 years ago

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If f(x)=-5^x and g(x)=-3x-2, find (f-g)(x) *high school*

-Dominant- [34]

Answer:

-5^x + 3x + 2

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(f - g)(x) = ƒ(x) -g(x) = -5^x -(-3x -2) = -5^x + 3x + 2

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sergij07 [2.7K]

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3 years ago

How do you simplify this? x²y+xy² / y²+2/5 × xy

polet [3.4K]

$\huge \boxed{\mathbb{QUESTION} \downarrow}$

How do you simplify this?
x²y+xy² / y²+2/5 × xy

$\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}$

$\sf\frac{ { x }^{ 2 } y+x { y }^{ 2 } }{ { y }^{ 2 } + \frac{ 2 }{ 5 } \times xy } \\$

Factor the expressions that are not already factored.

_____

How to factorise :-

NUMERATOR $\downarrow$

$\sf \: x ^ { 2 } y + x y ^ { 2 }$

Factor out xy.

$\sf \: xy\left(x+y\right)$

DENOMINATOR $\downarrow$

$\sf{ y }^{ 2 } + \frac{ 2 }{ 5 } \times xy \\$

Factor out 1/5.

$\sf \: {\frac{1}{5}y\left(2x+5y\right)} \\$

_____

Continuing...

$\sf\frac{xy\left(x+y\right)}{\frac{1}{5}y\left(2x+5y\right)} \\$

Cancel out y in both the numerator and denominator.

$\sf\frac{x\left(x+y\right)}{\frac{1}{5}\left(2x+5y\right)} \\$

Expand the expression.

$\sf\frac{x^{2}+xy}{\frac{2}{5}x+y} \\$

This can further simplified to as $\downarrow$

$= \boxed{\boxed{\bf\frac{5x\left(x +y\right)}{2x+5y}}}$

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3 years ago