What is the solution to this equation? 12(8)^x+1=24

Mathematics

2 answers:

Leto [7]2 years ago

5 0

Answer:

Step-by-step explanation:

aleksandrvk [35]2 years ago

4 0

It should add up to.
x= 0.312866

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Express this to single logarithm

zzz [600]

Answer: $\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right)$

We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.

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Explanation:

It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.

I'm going to use these three log rules, which apply to any base.

log(A) + log(B) = log(A*B)
log(A) - log(B) = log(A/B)
B*log(A) = log(A^B)

From there, we can then say the following:

$\frac{1}{2}\log_{2}\left(m\right)-3\log_{2}\left(n\right)+2\log_{2}\left(q\right)\\\\\log_{2}\left(m^{1/2}\right)-\log_{2}\left(n^3\right)+\log_{2}\left(q^2\right) \ \text{ .... use log rule 3}\\\\\log_{2}\left(\sqrt{m}\right)+\log_{2}\left(q^2\right)-\log_{2}\left(n^3\right)\\\\\log_{2}\left(\sqrt{m}*q^2\right)-\log_{2}\left(n^3\right) \ \text{ .... use log rule 1}\\\\\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right) \ \text{ .... use log rule 2}$

8 0

2 years ago

Consider the linear equation y=4x-7 find the value of y that makes the given ordered pair a solution to the equation (3, y) Y=

olchik [2.2K]

Y = 4x - 7 is a line with a slope of 4 and y-intercept of -7.

plug in any X value, for example 1 and you get the following

y = 4(1) - 7

y = -3

(1,-3) is a point that satisfies the equation y = 4x - 7

3 0

2 years ago

What percent of increase for a population that changed from 25,000 to 30,000

tiny-mole [99]

percent of increase for a population that changed from 25,000 to 30,000

Increase in population = 30,000 - 25,000 = 5000

So, the increase in population is 5000

To find percent of increase , we divide the increase in population by initial population.

So percent of increase = $\frac{5000}{25000}$ * 100