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2 years ago

Write down 2 factors of 10??

Mathematics

2 answers:

zaharov [31]2 years ago

3 0

2,5,1,10 that is what it is right bro

nikklg [1K]2 years ago

3 0

5/2/1/10 is factors of teen

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Meiling needs 5 dollars 35 cents to buy a ticket to a show. In her wallet, she finds 2 dollar bills, 11 dimes, and 5 pennies. Ho

Llana [10]

Answer:

no she needs $2.20 more

Step-by-step explanation:

2+ 1.10+.05= $3.15

$5.35 - $3.15 = the answer

5 0

2 years ago

Marta's jump rope is 10" shorter than four times the length of Dilbert's rope. If both their ropes laid together end to end and

sladkih [1.3K]

Answer:

Marta's rope is 94"

Step-by-step explanation:

D = dilberts rope length

M = marta's rope length

Marta's jump rope is 10" shorter than four times the length of Dilbert's rope

M = 4D-10

both their ropes laid together end to end and measured 120" long

M+D = 120

Substitute 4D-10 for M in the second equation

4D-10 + D = 120

Combine like terms

5D-10=120

Add 10 to each side

5D-10+10 =120+10

5D =130

Divide by 5

5D/5 = 130/5

D =26

Now we need to find M

M+D = 120

M +26 = 120

Subtract 26 from each side

M = 120-26

M = 94

3 0

3 years ago

I NEED HELP PLEASE, THANKS!! :)

Lisa [10]

Answer:

The answer is

$\frac{1372}{3} \pi \: {cm}^{3}$

Step-by-step explanation:

First you have to find the radius of sphere by dividing diameter by 2 :

$radius = diameter \div 2$

Let diameter = 14,

$radius = 14 \div 2$

$radius = 7 \: cm$

Next you have to use the volume of sphere formula :

$v = \frac{4}{3} \times \pi \times {r}^{3}$

Let r = 7,

$v = \frac{4}{3} \times \pi \times {7}^{3}$

$v = \frac{4}{3} \times \pi \times 343$

$v = \frac{1372}{3} \pi \: {cm}^{3}$

7 0

3 years ago

Write in scientific notation.

valina [46]

2.5 x 10^5

0.0 x 10^6

4 x 10^4

5 0

3 years ago

Read 2 more answers

Use the Quadratic Formula to solve x2 + 20x + 98 = 0

Lubov Fominskaja [6]

$ax^2+bx+c=0\\\\\Delta=b^2-4ac\\\\if\ \Delta \ \textless \ 0\ then\ no\ solution\\\\if\ \Delta =0\ then\ one\ solution\ x_0=\dfrac{-b}{2a}\\\\if\ \Delta \ \textgreater \ 0\ then\ two\ solutions\ x_1=\dfrac{-b-\sqrt\Delta}{2a}\ and\ x_2=\dfrac{-b+\sqrt\Delta}{2a}\\-----------------------------$

$x^2+20x+98=0\\a=1;\ b=20;\ c=98\\\\\Delta=20^2-4\cdot1\cdot98=400-392=8 \ \textgreater \ 0\\\sqrt\Delta=\sqrt8=\sqrt{4\cdot2}=\sqrt4\cdot\sqrt2=2\sqrt2\\\\x_1=\dfrac{-20-2\sqrt2}{2\cdot1}=\dfrac{-20-2\sqrt2}{2}=-10-\sqrt2\\\\x_2=\dfrac{-20+2\sqrt2}{2\cdot1}=\dfrac{-20+2\sqrt2}{2}=-10+\sqrt2$

3 0

3 years ago