The steps to determine whether the pillars have the same volume are;
First, we must know that the volume of an object of uniform surface area is the product of its Area and height.
The uniform area of each pillar is then evaluated and if equal;
Both pillars can be concluded to have the same volume.
We must first recall that for various shapes, the volume of the shape is a function of its height.
For example: a A cylinderical pillar and a rectangular prism pillar;
Volume of a cylinder = πr²h
Volume of a Cuboid = l × w × h
Since h = h.
Therefore, for both pillars to have the same volume; their Areas must be equal.
πr² = l × w
Learn more about Area and volume here
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25.8%
First, determine how many standard deviations from the norm that 3 tons are. So:
(3 - 2.43) / 0.88 = 0.57/0.88 = 0.647727273
So 3 tons would be 0.647727273 deviations from the norm. Now using a standard normal table, lookup the value 0.65 (the table I'm using has z-values to only 2 decimal places, so I rounded the z-value I got from 0.647727273 to 0.65). The value I got is 0.24215. Now this value is the probability of getting a value between the mean and the z-score. What I want is the probability of getting that z-score and anything higher. So subtract the value from 0.5, so 0.5 - 0.24215 = 0.25785 = 25.785%
So the probability that more than 3 tons will be dumped in a week is 25.8%
a) Unit rate = 24 oz / 10lb = 2.4 oz / lb
This means that we need 2.4 oz of seasoning for every pound of crawfish
b) For 30 lbs....we need 30 * 2.4 = 72 oz of seasoning
c) With 36 oz of seasoning...we can cook 36 / 2.4 = 15 lbs of crawfish
<h3>
Answer: x^2-3x+36</h3>
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Explanation:
The larger rectangle has area of (x+1)(x+1) = x^2+2x+1 through the use of the FOIL rule or distribution
If you use distribution, then it might help to let y = x+1 so we'd have y(x+1) lead to xy+1y which becomes x(x+1)+1(x+1). From there it might be easier to see how to get x^2+2x+1 after everything distributes again and simplifies.
The smaller rectangle has area 5x-35 which is found by distributing 5(x-7)
To get the shaded area, we subtract the two rectangle areas found above
shaded area = (larger area) - (smaller area)
shaded area = (x^2+2x+1) - (5x - 35)
shaded area = x^2+2x+1 - 5x + 35
shaded area = x^2-3x+36
