Answer:
<em>The first step is to determine the average
</em>

<em>The exercise says it’s a normal distribution: (n=8)</em>

<em>According to the exercise, the mean is equal to 0,5 then the value of t of the distribution can be obtained
</em>
<em />

<em>The variable t has 7 grade to liberty, we calculate the p-value as:
</em>

This value is very high, therefore the hypothesis is not rejected
Answer:
See explanation below.
Step-by-step explanation:
Given: 100 lbs on Earth is 16.6 lbs on the moon.
a. The independent variable is weight. The gravity of the Moon and the gravity of the Earth are constant. Weight can change, but gravity is a constant.
b. An equation that relates the weight of someone on the Moon who travels to the Earth:
100 / 16.6 = 6.02. Take the Moon weight and multiply by 6.02:
Moon Weight * 6.02 = Earth Weight.
Proof:
16.6 * 6.024 = 99.99 - approximately 100 lbs Earth weight.
c. A 185 lb astronaut on Earth would weigh:
16.6 / 100 = .166. Take the Earth weight and multiply by .166:
185 * .166 = 30 lbs on the Moon.
d. A person who weighs 50 lbs on the Moon:
50 * 6.024 = 301.2 lbs on Earth.
Hope this helps! Have a good day and year! :)
Answer:
0.66 = 66%
Step-by-step explanation:
If we know that a odd-numbered disk is selected, we know that the number is 1, 3 or 5.
So, if it is a red disk, is can be number 1 or 3, so we have two possibilities.
If it is a yellow disk, it needs to be number 5, so we have just one possibility.
We have a total of 3 possibilities, and 2 of them are with red disks, so the probability is 2/3 = 0.66 = 66%
x = 2a
a = 3
x = 2 · 3 = 6 ← the end answer
9hours x 60minutes = 540 minutes
(Presuming he actually sat and read the whole time)