Answer:
This would not be an appropriate sampling technique because it is biased and it would not be fair for 60 students to choose a mascot for a school with 800 students.
Step-by-step explanation:
4. SOLVE FOR X:
Using the Alternate Interior Angles Theorem, we know that the 67 degree angle is congruent with the (12x - 5) degree angle. With this information, all I have to do is set the two equal to each other and solve for x.
67 = 12x - 5
67 + 5 = 12x - 5 + 5
72/12 = 12x/12
6 = x
x = 6
SOLVE FOR Y:
Using the Vertical Angles theorem, we know that angle y must be congruent to the 67 degree angle.
y = 67 degrees.
5. SOLVE FOR Y:
Alternate exterior angles: 6(x - 12) = 120
6x - 72 + 72 = 120 + 72
6x/6 = 192/6
x = 32
SOLVE FOR Y:
6((32) - 12) + y = 180
192 - 72 + y = 180
120 + y - 120 = 180 - 120
y = 60
Answer:
0.3557 = 35.57% probability that one selected subcomponent is longer than 118 cm.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Normally distributed with a mean of 116 cm and a standard deviation of 5.4 cm.
This means that 
Find the probability that one selected subcomponent is longer than 118 cm.
This is 1 subtracted by the pvalue of Z when X = 118. So
has a pvalue of 0.6443
1 - 0.6443 = 0.3557
0.3557 = 35.57% probability that one selected subcomponent is longer than 118 cm.
G(x) = 6x
<span>g(f(x)) </span>
<span>= 6((x^2) - 5) </span>
<span>= (6x^2) - 30
</span>
so its equal to
<span>(6x^2) - 30</span>
0° 42' 48.6".
Conversion: d = int(.7135°) = 0°m = int((.7135° - 0°) × 60) = 42's = (.7135° - 0° - 42'/60) × 3600 = 48.6".7135°= 0° 42' 48.6"
How to convert decimal degrees to degrees,minutes,secondsOne degree (°) is equal to 60 minutes (') and equal to 3600 seconds ("):
1° = 60' = 3600"
The integer degrees (d) are equal to the integer part of the decimal degrees (dd):
d = integer(dd)
The minutes (m) are equal to the integer part of the decimal degrees (dd) minus integer degrees (d) times 60:
m = integer((dd - d) × 60)
The seconds (s) are equal to the decimal degrees (dd) minus integer degrees (d) minus minutes (m) divided by 60 times 3600:
s = (dd - d - m/60) × 3600
