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Dovator [93]
3 years ago
5

URGENT!!!! Set up proportions for each variable and solve!!! I have a test tomorrow and have no clue how to do proportions!

Mathematics
1 answer:
vlada-n [284]3 years ago
8 0

Answer:

This is how you do proportions (images below). If you need more help just ask.

Step-by-step explanation:

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5<3x+2<11 solve the compound inequality
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5 < 3x+2 < 11

Subtract 2 all terms:

3 < 3x < 9

Divide all terms by 3:

1 < x < 3

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Please help with question 11! BRAINLIEST to correct answer!!
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Answer:

No

Step-by-step explanation:

you can see that they can not go into each other and come out correct so the answer would have to be no (we were working on this same thing)

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Write three value that makes 3 &gt; x true How do you know?
natita [175]

Answer:

3>2

3>1

3>0

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2 years ago
84&gt; -4(6x-3) I don't know what the answer is. Can someone please help me?
nata0808 [166]

Answer:

x>−3

Step-by-step explanation:

Step 1: Simplify both sides of the inequality.

84>−24x+12

Step 2: Flip the equation.

−24x+12<84

Step 3: Subtract 12 from both sides.

−24x+12−12<84−12

−24x<72

Step 4: Divide both sides by -24.

−24x /−24 < 72 /−24

7 0
3 years ago
Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line.
kramer

Step-by-step explanation:

A cross-section is a washer with an inner radius of 8sin(x) - (-1) and an outer radius of 8cos(x) - -(1), so its area would be:

A(x) = π[(8cos(x) + 1)^2 − (8sin(x) + 1)^2]

= π[64cos^2(x) + 16cos(x) + 1 - 64sin^2(x) − 16sin(x) − 1]

= π[64cos(2x) + 16cos(x) - 16sin(x)]

=> V(x) = ∫[0,π/4] π[64cos(2x) + 16cos(x) - 16sin(x)] dx

= π[32sin(2x) + 16sin(x) + 16cos(x)] |[0,π/4]

= π[32sin(π/2) + 16√2/2 + 16√2/2 - 16]

= π(32 - 16 + 16√2) = π(16 + 16√2)

The volume of the region is π(16 + 16√2).

7 0
3 years ago
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