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erma4kov [3.2K]
3 years ago
12

This is a question on proportions in geometry. Image has been shared.

Mathematics
2 answers:
Digiron [165]3 years ago
7 0
A+b       5
------- = ---
2a-b      4

  b           5
-------- = ----  => 9b = 5a+45 => b = (5a+45)/9
 a+9       9


a+b       5
------- = --- => 4a+4b = 10a-5b
2a-b      4

9b = 6a

9(5a+45) =6a   divide both sides by 3

3(5a+45) = 2a

15a +135 = 2a

13a = -135

a = -135/13 = -10,38

a= -10,38

9b=6a

3b=2a

3b = 2(-10,38)

3b = -20,76

b = -20,76/3

b = -6,92

hope this helped 
VikaD [51]3 years ago
4 0
(a + b)/(2a - b) = 5/4                    b/(a + 9) = 5/9

4*(a + b) = 5*(2a - b)

4a + 4b = 10a - 5b

4a - 10a = -5b - 4b

-6a = -9b

6a = 9b............(a)


<span> b/(a + 9) = 5/9</span>

9*b = 5*(a + 9)

9b = 5a + 45           Recall from (a) 9b = 6a

6a = 5a + 45

6a - 5a = 45

a = 45

9b =  6a

9b = 6*45

b = 6*45/9 = 30

a = 45, b = 30
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Please help me with this <br><br> Will mark brainliest!
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Answer:

therefore carlos walks much faster.

Explanation:

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2 years ago
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What is Mario's cycling rate?<br> miles per hour
Yuliya22 [10]

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Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A TV show, Lindsay and Tobias, recently had a share of 20, meaning that among the TV sets in use, 20% were tuned to that show. A
kati45 [8]

Answer:

8.6% probability that none of the households are tuned to Lindsay and Tobias.

There is a 91.4% probability that at least one household is tuned to Lindsay and Tobias.

There is a 32.2% probability that at most one household is tuned to Lindsay and Tobias.

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they are watching the TV show, or they are not. This means that we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 11, p = 0.20

Find the probability that none of the households are tuned to Lindsay and Tobias.

This is P(X = 0).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{11,0}.(0.20)^{0}.(0.80)^{11} = 0.086

8.6% probability that none of the households are tuned to Lindsay and Tobias.

Find the probability that at least one household is tuned to Lindsay and Tobias.

Either no household is tuned, or at least one is tuned. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.086 = 0.914

There is a 91.4% probability that at least one household is tuned to Lindsay and Tobias.

Find the probability that at most one household is tuned to Lindsay and Tobias.

This is

P(X \leq 1) = P(X = 0) + P(X = 1)

P(X = 1) = C_{11,1}.(0.20)^{1}.(0.80)^{10} = 0.236

P(X \leq 1) = P(X = 0) + P(X = 1) = 0.086 + 0.236 = 0.322

There is a 32.2% probability that at most one household is tuned to Lindsay and Tobias.

8 0
3 years ago
Image attached<br> filler<br> filler<br> filler
zloy xaker [14]

Answer:

The answer will be A

Step-by-step explanation:

have a nice day/night

8 0
3 years ago
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