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3 years ago

What is the x and y intercept of each equation?

Mathematics

2 answers:

aniked [119]3 years ago

8 0

To find the x-intercept you plug 0 in for y and solve for x

To find the y-intercept you plug 0 in for x and solve for y

20x + 8(0) = 240
20x = 240
x = 12

20(0) + 8y = 240
8y = 240
y = 30

For the first equation your x-intercept is (12,0) and your y-intercept is (0,30)

15x + 3(0) = 270
15x = 270
x = 18

15(0) + 3y = 270
3y = 270
y = 90

For the second equation your x-intercept is (18,0) and your y-intercept is (0,90)

Talja [164]3 years ago

4 0

The "x" intercept is where a line would mark across the "x" axis.

The "y" intercept is where a line would mark across the "y" axis.

X is horizontal and Y is vertical.

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leonid [27]

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3 years ago

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3 years ago

- 16 = -4(-5+ i) Please help i can’t fail this test

Simora [160]

Answer: i=9

Step-by-step explanation:

-16=-4(-5+i)

-16=20-4i

-20 -20

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3 years ago

Read 2 more answers

Select the correct answer. What is the solution to the equation?

Ierofanga [76]

Answer:

Step-by-step explanation:

$\sqrt{x}$ + 6 = x ( subtract 6 from both sides )

$\sqrt{x}$ = x - 6 ( square both sides )

x = (x - 6)² ← expand using FOIL

x = x² - 12x + 36 ( subtract x from both sides )

0 = x² - 13x + 36 , that is

x² - 13x + 36 = 0 ← in standard form

(x - 4)(x - 9) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 4 = 0 ⇒ x = 4

x - 9 = 0 ⇒ x = 9

As a check

Substitute these values into the equation and if both sides are equal then they are the solutions.

x = 4

left side = $\sqrt{4}$ + 6 = 2 + 6 = 8

right side = x = 4

Since 8 ≠ 4 then x = 4 is an extraneous solution

x = 9

left side = $\sqrt{9}$ + 6 = 3 + 6 = 9

right side = x = 9

Thus the solution is x = 9 → B

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3 years ago