What is the ratio of a:c?

To plan the budget for next year a college must update its estimate of the proportion of next year's freshmen class that will ne

Naily [24]

Answer:

Null hypothesis: $p\leq 0.35$

Alternative hypothesis: $p > 0.35$

$z=\frac{0.447 -0.35}{\sqrt{\frac{0.35(1-0.35)}{150}}}=2.491$

$p_v =P(z>2.491)=0.0064$

So the p value obtained was a very low value and using the significance level assumed $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of applicants who request financial aid is significantly higher than 0.35

Step-by-step explanation:

Data given and notation

n=150 represent the random sample taken

X=67 represent the applicants who request financial aid

$\hat p=\frac{67}{150}=0.447$ estimated proportion of applicants who request financial aid

$p_o=0.35$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion of applicants who request financial aid is higher than 0.35.:

Null hypothesis: $p\leq 0.35$

Alternative hypothesis: $p > 0.35$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.447 -0.35}{\sqrt{\frac{0.35(1-0.35)}{150}}}=2.491$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>2.491)=0.0064$

So the p value obtained was a very low value and using the significance level assumed $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of applicants who request financial aid is significantly higher than 0.35

5 0

3 years ago

In a poultry farm, 50 hens give 200 eggs in 2 days. In how many days will 20 hens give 400 eggs?.

s344n2d4d5 [400]

The number of days is 10 if, in a poultry farm, 50 hens give 200 eggs in 2 days.

<h3>What is a fraction?</h3>

Fraction number consists of two parts, one is the top of the fraction number which is called the numerator and the second is the bottom of the fraction number which is called the denominator.

It is given that:

On a poultry farm, 50 hens give 200 eggs in 2 days.

It is required to find the number of days will 20 hens require to give 400 eggs:

Let x be the number of days:

(50×2)/200 = (20x)/400

x = 10

Thus, the number of days is 10 if, in a poultry farm, 50 hens give 200 eggs in 2 days.

Learn more about the fraction here:

brainly.com/question/1301963

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6 0

1 year ago

Something times something that equals 7

Anestetic [448]

Well since two solid numbers cant make 7 I would do 3.5 x 7

3 0

3 years ago

Read 2 more answers

The length of & rectangle is 3 times the

vagabundo [1.1K]

Answer:

The answer for this question is C, E and F .

Step-by-step explanation:

Given that the length is 3 times the width. So firstly, you have to find the expression of length :

$length = 3 \times width$

Let width = w,

$length = 3 \times w$

$length = 3w$

Next, the perimeter of rectangle is P = 2(length+width) so you have to substitute the expression into the formula :

$p = 2(length + width)$

Let length = 3w,

Let width = w,

$p = 2(3w + w) \: \: (option \: e)$

$p = 2(3w) + 2(w) \: \: (option \: f)$

$p = 6w + 2w$

$p = 8w \: \: (option \: c)$

6 0

3 years ago

A pathologist has been studying the frequency of bacterial colonies within the field of a microscope using samples of throat cul

nata0808 [166]

Answer:

P(0) = 0.055

P(1) = 0.16

P(2) = 0.231

P(3) = 0.224

P(4) = 0.162

P(5 or more) = 0.168

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Here λ = 2.90 is the average number of bacteria colonies per field.

This means that $\mu = 2.90$

Compute P(r) for r = 0, 1, 2, 3, 4, and 5 or more.

$P(0) = \frac{e^{-2.9}*(2.9)^{0}}{(0)!} = 0.055$

$P(1) = \frac{e^{-2.9}*(2.9)^{1}}{(1)!} = 0.16$

$P(2) = \frac{e^{-2.9}*(2.9)^{2}}{(2)!} = 0.231$

$P(3) = \frac{e^{-2.9}*(2.9)^{3}}{(3)!} = 0.224$

$P(4) = \frac{e^{-2.9}*(2.9)^{4}}{(4)!} = 0.162$

5 or more:

This is

$P(X \geq 5) - 1 - P(X < 5)$

In which:

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.055 + 0.16 + 0.231 + 0.224 + 0.162 = 0.832$

$P(X \geq 5) - 1 - P(X < 5) = 1 - 0.832 = 0.168$

So

P(5 or more) = 0.168

7 0

3 years ago