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4 years ago

Find the value of x. (5x+15) (6x-10)

Mathematics

2 answers:

Annette [7]4 years ago

7 0

Answer:

We get x = -5/3 and x = -3

Step-by-step explanation:

$(5x+15) (6x-10)$

Multiplying this and equating to zero, to find x.

$30x^{2} -50x+90x-150=0$

$30x^{2} +40x-150=0$

Factoring out 10.

$3x^{2} +4x-15=0$

$3x^{2} +9x-5x-15=0$

3x(x+3)-5(x+3)=0 $[tex](3x-5)(x+3)=0$ [/tex]

We get x = -5/3 and x = -3

Blizzard [7]4 years ago

4 0

(5x+15)(6x-10)
= 30x^2 + 30x - 50x - 150
= 30x^2 - 20x - 150

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4 years ago

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densk [106]

Answer:

$A.\ y = x^2 - 6x + 13$ is the correct answer.

Step-by-step explanation:

We know that vertex equation of a parabola is given as:

$y = a(x-h)^2+k$

where $(h,k)$ is the vertex of the parabola and

$(x,y)$ are the coordinate of points on parabola.

As per the question statement:

The parabola opens upwards that means coefficient of $x^{2}$ is positive.

Let $a = +1$

Minimum of parabola is at x = 3.

The vertex is at the minimum point of a parabola that opens upwards.

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Putting value of a and h in the equation:

$y = 1(x-3)^2+k\\\Rightarrow y = (x-3)^2+k\\\Rightarrow y = x^2-6x+9+k$

Formula used: $(a-b)^2=a^{2} +b^{2} -2\times a \times b$

Comparing the equation formulated above with the options given we can observe that the equation formulated above is most similar to option A.

Comparing $y = x^2 - 6x + 13$ and $y = x^2-6x+9+k$

13 = 9+k

k = 4

Please refer to the graph attached.

Hence, correct option is $A.\ y = x^2 - 6x + 13$

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