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Komok [63]
4 years ago
9

How would you solve 3x^2-12=0?

Mathematics
1 answer:
Gennadij [26K]4 years ago
3 0

                                                                                 3x^2 - 12  =  0

Personally, I would divide each side by 3                x^2 - 4  =  0

Then I would add 4 to each side                              x^2        =  4

Then I would take the square root of each side:     x  =  +4
                                                                                     x  =  -4 .

Having found both solutions, I would relax with a cup of tea.

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Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x' to each side of the equation.

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Combine like terms: x + -3x = -2x

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12 + -12 + -2x = -22 + -12

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