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Komok [63]
3 years ago
9

How would you solve 3x^2-12=0?

Mathematics
1 answer:
Gennadij [26K]3 years ago
3 0

                                                                                 3x^2 - 12  =  0

Personally, I would divide each side by 3                x^2 - 4  =  0

Then I would add 4 to each side                              x^2        =  4

Then I would take the square root of each side:     x  =  +4
                                                                                     x  =  -4 .

Having found both solutions, I would relax with a cup of tea.

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–2x + 2y = -4<br> 3х + Зу = -18
rodikova [14]

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(-2, -4)

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-------------------

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