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UkoKoshka [18]
3 years ago
5

What is the volume of the composite figure?

Mathematics
1 answer:
ehidna [41]3 years ago
7 0

\huge\boxed{\text{C.}\ 372\ \text{cubic inches}}

We will find the volume of each rectangular prism separately.

<h3>Top Figure</h3>

12*4*4

12*16

\boxed{192}

<h3>Bottom Figure</h3>

12*5*3

12*15

\boxed{180}

<h3>Adding Together</h3>

192+180

\large\boxed{372\ \text{in}^{3}}

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3 years ago
Bob and will toss two coins. if both coins come up heads, bob pays will $6. will pays bob $2 otherwise. what is the expected val
Helga [31]
Each coin has a head and a tail, therefore when you toss two coins, you have 4 possible outcomes. You have two heads in only one of these outcomes, while the other three have at least one tail.

The expected value of the game is the price paid/gained times the probability of loss/victory:

E = (1 / 4) · (-6) + (3 / 4) · (2)
   = -3 / 2 + 3 / 2
   = 0

Bob expects to tie with Will.


6 0
3 years ago
Read 2 more answers
In the solution to this system, what is the value of y? x+y+z=1x+y+z=1 2x+y−z=82x+y-z=8 x−y+z=−5
kirza4 [7]
If you have multiple equations with multiple variables, you can either do clever substitutions, or turn it into a matrix on which you can perform linear combinations or multiplications (Gauss elimination)

1  1   1  1
2  1  -1  8
1 -1   1  -5

(note how the above 3 rows represent the 3 equations, just got rid of the variables, plus sign and equals sign)

subtract row1 from row3, that eliminates x and z from row 3.

1  1   1  1
2  1  -1  8
0 -2   0  -6

divide row3 by -2, that will give y a factor of 1

1  1   1  1
2  1  -1  8
0 1   0  3

The last row now says y=3



3 0
3 years ago
Graph the line for y+1=−3/5(x−4) on the coordinate plane
Andrej [43]
Solve for y:
y + 1 = -3/5x + 2.4  (multiply 4 by 3/5 no negatives because negative times a negative is a positive)
y = -3/5x + 1.4
Now graph the y-intercept of 1.4. 
Then plot points using slope. 
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7 0
3 years ago
The half life of uranium-232 is 68.9 years. (show step by step)
dalvyx [7]

Answer:

1.) 8.09g ; 2) 206.7 years

Step-by-step explanation:

Given the following :

Half-life(t1/2) of Uranium-232 = 68.9 years

a) If you have a 100 gram sample, how much would be left after 250 years?

Initial quantity (No) = 100g

Time elapsed (t) = 250 years

Find the quantity of substance remaining (N(t))

Recall :

N(t) = No(0.5)^(t/t1/2)

N(250) = 100(0.5)^(250/68.9)

N(250) = 100(0.5)^3.6284470

N(250) = 100 × 0.0808590

= 8.0859045

= 8.09g

2) If you have a 100 gram sample, how long would it take for there to be 12.5 grams remaining?

Using the relation :

N / No = (1/2)^n

Where N = Amount of remaining or left

No = Original quantity

n = number of half-lifes

N = 12.5g ; No = 100g

12.5 / 100 = (1/2)^n

0.125 = (1/2)^n

Converting 0.125 to fraction

(1/8) = 1/2^n

8 = 2^n

2^3 = 2^n

n = 3

Recall ;

Number of half life's (n) = t / t1/2

t = time elapsed ; t1/2 = half life

3 = t / 68.9

t = 3 × 68.9

t = 206.7 years

7 0
2 years ago
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