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garik1379 [7]
2 years ago
7

Find constants A and B such that (x + 7)/(x^2 - x - 2) = A/(x - 2) + B/(x + 1) for all x such that x≠ -1 and x≠ 2 Give your answ

er as the ordered pair (A,B).
Mathematics
1 answer:
Yanka [14]2 years ago
6 0
For this case we have the following expression:
 (x + 7) / (x ^ 2 - x - 2) = A / (x - 2) + B / (x + 1)
 Rewriting we have:
 (x + 7) / ((x-2) (x + 1)) = A / (x - 2) + B / (x + 1)
 We multiply the equality by (x-2) (x + 1):
 x + 7 = A (x + 1) + B (x - 2)
 Rewriting we have the following system of equations:
 A + B = 1
 A - 2B = 7
 Solving the system we have:
 A = 3
 B = -2
 Answer:
 
constants A and B are:
 
A = 3
 
B = -2
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3 years ago
How do I find the missing value
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