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To function properly, a rainwater outflow pipe must drop 1 inch every 25 inches of horizontal distance. A 40 feet long rainwater
2 answers:
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Answer:
Mass of the cat = 16800kg
Step-by-step explanation:
The volume of the box = its length * its breath * its height- 4m × 3m × 2m = 24
The standard density of water is 1000 Kg/
By Archimedes principle, the mass of a body floating body is equivalent to the mass of the volume liquid displaced
in this case we have
Mass of water displaced = Density of the water × Volume of the water displaced = 1000 Kg/ × 24
= 24000kg
The mass of the box = Box density × Box volume = 24 × 300kg/
= 7200 kg Hence the mass of water displaced = mass of the foating box + mass of th cat
24000kg = mass of cat +7200kg
mass of cat = 24000kg - 7200kg = 16800kg