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2 years ago

Can someone help me with this question

Mathematics

2 answers:

Viefleur [7K]2 years ago

6 0

i Cannot see the number but. MOST likely yes

Step-by-step explanation:

Alex_Xolod [135]2 years ago

3 0

Answer:

Yes.

Step-by-step explanation:

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How to solve this equation 7-2a-5-14=-2+3a

SSSSS [86.1K]

To solve 7-2a-5-14=-2+3a :

1) combine like terms: 7-19 - 2a = -2 + 3a, and then -10 = 5a

2) solve this equation for a: a = -10/5 = -2.

The solution of 7-2a-5-14=-2+3a is a = -2.

6 0

3 years ago

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HELP DUE IM THIRTY MINUTES

Alexandra [31]

Answer:

I do not know this answer to the question. I am so sorry. Ask "LucasPeed"

Step-by-step explanation:

If you need anymore help ask, Brainly. Have a nice day!

6 0

2 years ago

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Find the volume of the solid.

dmitriy555 [2]

In Cartesian coordinates, the region (call it $R$ ) is the set

$R = \left\{(x,y,z) ~:~ x\ge0 \text{ and } y\ge0 \text{ and } 2 \le z \le 4-x^2-y^2\right\}$

In the plane $z=2$ , we have

$2 = 4 - x^2 - y^2 \implies x^2 + y^2 = 2 = \left(\sqrt2\right)^2$

which is a circle with radius $\sqrt2$ . Then we can better describe the solid by

$R = \left\{(x,y,z) ~:~ 0 \le x \le \sqrt2 \text{ and } 0 \le y \le \sqrt{2 - x^2} \text{ and } 2 \le z \le 4 - x^2 - y^2 \right\}$

so that the volume is

$\displaystyle \iiint_R dV = \int_0^{\sqrt2} \int_0^{\sqrt{2-x^2}} \int_2^{4-x^2-y^2} dz \, dy \, dx$

While doable, it's easier to compute the volume in cylindrical coordinates.

$\begin{cases} x = r \cos(\theta) \\ y = r\sin(\theta) \\ z = \zeta \end{cases} \implies \begin{cases}x^2 + y^2 = r^2 \\ dV = r\,dr\,d\theta\,d\zeta\end{cases}$

Then we can describe $R$ in cylindrical coordinates by

$R = \left\{(r,\theta,\zeta) ~:~ 0 \le r \le \sqrt2 \text{ and } 0 \le \theta \le\dfrac\pi2 \text{ and } 2 \le \zeta \le 4 - r^2\right\}$

so that the volume is

$\displaystyle \iiint_R dV = \int_0^{\pi/2} \int_0^{\sqrt2} \int_2^{4-r^2} r \, d\zeta \, dr \, d\theta \\\\ ~~~~~~~~ = \frac\pi2 \int_0^{\sqrt2} \int_2^{4-r^2} r \, d\zeta\,dr \\\\ ~~~~~~~~ = \frac\pi2 \int_0^{\sqrt2} r((4 - r^2) - 2) \, dr \\\\ ~~~~~~~~ = \frac\pi2 \int_0^{\sqrt2} (2r-r^3) \, dr \\\\ ~~~~~~~~ = \frac\pi2 \left(\left(\sqrt2\right)^2 - \frac{\left(\sqrt2\right)^4}4\right) = \boxed{\frac\pi2}$

3 0

1 year ago

Mary is getting up a fence for her square garden.The garden has an area of 100 square feet.How long will each side of fence have

saw5 [17]

It would be 25 feet 25x4= 100

7 0

2 years ago

96/120 as a percentage

ivann1987 [24]

96÷120 =0.8 ⇒0.8 ×100 =80 % :))

7 0

3 years ago

Read 2 more answers