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Goshia [24]
3 years ago
8

Can effective distance learning interaction be achieved on a low-bandwidth mobile device? Your answer should be 3 sentences.

Computers and Technology
1 answer:
natima [27]3 years ago
7 0

Answer:

No, this is not possible. Due to low bandwidth, neither video nor teleconferencing will be possible. Moreover, large size study materials will take quite a while to be downloaded and uploaded. And hence, it will be very difficult to ensure distance learning online as student-student, and student-teacher as well as teacher-teacher, and management-teacher-student interaction will be very difficult.

Explanation:

Please check the answer section.

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Some of them do let you draw funds but not all debit cards
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Assume that the ciphertext C is computed from the plaintext P by C= P ⊕ K1 ⊕ K2 , where K1 and K2 are the encryption key and ⊕ d
Sedbober [7]

Answer:

K1 ⊕ K2 = 9

Explanation:

Since 5 ⊕ K = 12, K must be 5 ⊕ 12 = 9.

But there are supposedly two encryptionkeys, we cannot know their individual value, only that K1 ⊕ K2 = 9.

That makes this a bit weird question.

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Why does Brainly say, "We're sorry, but we are not able to complete your registration at this time?" Please tell me, because I r
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3 years ago
After successfully building a machine language version of thePascal compiler, one could in principle discard the P-code interpre
MA_775_DIABLO [31]

Answer:

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Explanation:

6 0
3 years ago
1. Write a method isMultiple that determines, for a pair of integers, whether the second integer is a multiple of the first. The
zhannawk [14.2K]

Answer:

see explaination for code

Explanation:

Implement using JAVA

import java.util.Scanner;

public class Multiples {

public static boolean isMultiple(int first, int second){

if(second%first == 0)

return true;

else

return false;

}

public static void main(String[] args) {

Scanner sc = new Scanner(System.in);

while(true){

System.out.print("Enter one number: ");

int first = sc.nextInt();

System.out.print("Enter a second number: ");

int second = sc.nextInt();

if(isMultiple(first, second))

System.out.println(second+" is multiple of "+first);

else

System.out.println(second+" is not multiple of "+first);

System.out.print("Do you want to enter another pair(y/n)? ");

char c = sc.next().charAt(0);

if('y' != Character.toLowerCase(c))

break;

}

}

}

/*

Sample run:

Enter one number: 7

Enter a second number: 28

28 is multiple of 7

Do you want to enter another pair(y/n)? y

Enter one number: 8

Enter a second number: 24

24 is multiple of 8

Do you want to enter another pair(y/n)? y

Enter one number: 4

Enter a second number: 2

2 is not multiple of 4

Do you want to enter another pair(y/n)? n

*/

8 0
3 years ago
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