Question

What are the solutions to the equation and check for extraneous solutions: 16=(x-2)^2/3

Answer 1

Answer:

we have  x = -62 or x = 66

Step-by-step explanation:

16=(x-2)^2/3

I would take square root first

4 =  (x - 2)^ (1/3)

or   -4  =  (x - 2)^(1/3)

.....

4^3  =  x - 2

64 = x - 2

x = 66

or  -4 ^3 = x - 2

-64 = x - 2

x = -62

we have  x = -62 or x = 66