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3 years ago

What are the solutions to the equation and check for extraneous solutions: 16=(x-2)^2/3

Mathematics

1 answer:

GuDViN [60]3 years ago

5 0

Answer:

we have x = -62 or x = 66

Step-by-step explanation:

16=(x-2)^2/3

I would take square root first

4 = (x - 2)^ (1/3)

or -4 = (x - 2)^(1/3)

.....

4^3 = x - 2

64 = x - 2

x = 66

or -4 ^3 = x - 2

-64 = x - 2

x = -62

we have x = -62 or x = 66

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2 years ago

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2 years ago

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postnew [5]

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3 years ago

Evaluate 3x+6y when x= -3, y=6

sesenic [268]

Hey there!!!

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