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Svetlanka [38]
4 years ago
5

What are the solutions to the equation and check for extraneous solutions: 16=(x-2)^2/3

Mathematics
1 answer:
GuDViN [60]4 years ago
5 0

Answer:

we have  x = -62 or x = 66

Step-by-step explanation:

16=(x-2)^2/3

I would take square root first

4 =  (x - 2)^ (1/3)

or   -4  =  (x - 2)^(1/3)

.....

4^3  =  x - 2

64 = x - 2

x = 66

or  -4 ^3 = x - 2

-64 = x - 2

x = -62

we have  x = -62 or x = 66

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If y = -5x + 2 were changed to y=-7x+ 5, how would the graph of the new line compare with the first one? A. The new graph would
Anika [276]

D- The new graph would be steeper than the original graph, and the y- intercept would shift up 3 units.

The purple line is y=-5x + 2

The pink line is y = -7x + 5

5 0
3 years ago
A rubber ball is dropped from a height of 50 feet. Assume that each bounce of the ball is vertical
Julli [10]

Answer:

You left out a critical piece of information in the question.

"reaches a height of of the maximum height"

Step-by-step explanation:

4 0
3 years ago
What is 6 1/2 + 10? please tell me and explain for me to understand
ipn [44]

Answer:

33/2

Step-by-step explanation:

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5 0
3 years ago
−5/8+3/4 equals what, In fraction form.
kipiarov [429]

How to get answer by Mimiwhatsup (In Decimal Form):

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7 0
3 years ago
The LCM of 2 numbers is 60 and 1 of the numbers is 7 less than the other number. What are the numbers?
Phoenix [80]
Let's represent the two numbers by x and y.  Then xy=60.  The smaller number here is x=y-7.

Then (y-7)y=60, or y^2 - 7y - 60 = 0.  Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:

discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191.  Because the discriminant is positive, this equation has two real, unequal roots, which are
        -(-7) + sqrt(191)
y = -------------------------
             -2(1)

and 

        -(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
             -2(1)

Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.


Try thinking this way:  If the LCM is 60, then xy = 60.  What would happen if x=5 and y=12?  Is xy = 60?  Yes.  Is 5 seven less than 12?  Yes.






5 0
3 years ago
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