<em>BD</em> = 56
Step-by-step explanation:
Step 1: In rectangle, the diagonals are congruent and bisect each other.
So, <em>AC</em> = <em>BD</em>
⇒<em>AG</em> + <em>GC</em> = <em>BG</em> + <em>GD</em>
⇒<em>AG</em> + <em>AG</em> = <em>GD</em> + <em>GD</em>
⇒ 2<em>AG</em> = 2<em>GD</em>
⇒<em>AG</em> = <em>GD</em>
⇒ –7<em>j </em>+ 7 = 5<em>j</em> + 43
⇒–7<em>j</em> – 5<em>j</em> = 43 – 7
⇒–12<em>j</em> = 36
⇒<em>j</em> = –3
Step 2: <em>BD</em> = 2<em>DG</em>
<em>BD</em> = 2(5<em>j</em> + 43)
= 2(5 (–3) + 43)
= 2(–15 + 43)
= 2 × 28
= 56
Hence, <em>BD</em> = 56.
(-1,-1)(-3,-3)
slope = (-3 - (-1) / (-3 - (-1) = (-3 + 1) / (-3 + 1) = -2/-2 = 1
W/4 divide the two to find the quotient
Answer:
q = -13.2
Step-by-step explanation:
9.7q = 9.1q - 7.92
Subtract 9.1q from both sides.
0.6q = -7.92
Divide both sides by 0.6
q = -13.2
Double check your work.
9.7(-13.2) = 9.1(-13.2) - 7.92
-128.04 = -120.12 - 7.92
-128.04 = -128.04
Answer:
3
Step-by-step explanation:
An average railroad car has a weight of about 33 tons.
120 tons of freight is equivalent to 120/4 = 3.64 cars
that means that, for the operator to be able to haul 120 tons of freight, he has to haul at least 3 cars to break even.
