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romanna [79]
3 years ago
5

Simply 8x squared + 5(7x squared- x) - 2x =

Mathematics
1 answer:
Slav-nsk [51]3 years ago
4 0
Suuuuree,

8 {x}^{2}  + 5(7 {x}^{2}   - x) - 2x \\  \\ 8 {x}^{2}  + 35 {x}^{2}  - 5x - 2x \\  \\ 43 {x}^{2}  - 7x
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Need geometry help ASAP please!
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Answer:

1. 121 π  unit²

2. 143°

3. 151 unit²

Step-by-step explanation:

1.

Area of a circle is given by the formula  A = πr²

where

A is the area,

r is the radius of the circle

From the given diagram, we can see that the radius is 11, hence the area will be:

A=\pi r^2\\A=\pi (11)^2\\A=121\pi

The answer is  121\pi units^2

2.

The unshaded secctor and the shaded sector equals the circle. We know that circle is 360°. The unshaded sector has an angle of 217°. So the shaded part will be 360 - 217 = 143°

The measure of the central angle of the shaded sector is 143°

3.

Area of a sector is given by the formula  A=\frac{\theta}{360}*\pi r^2

Where

\theta is the central angle of the sector (in our case it is 143°)

r is the radius (which is 11)

Plugging in all the info into the formula we have:

A=\frac{\theta}{360}*\pi r^2\\A=\frac{143}{360}*\pi (11)^2\\A=150.99

<em>rounding to the nearest whole number, it is </em>151 units^2

3 0
3 years ago
Randell earns $8 per hour at his job. if he works more than 40 hours, he earns 1 1/2 times his normal hourly rate. if Randall wo
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Assume that two chords in a given circle are the same distance from the
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Step-by-step explanation:

If the two chords are congruent, then they must be equidistant from the centre of the circle.

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B is rejected because the chords are not obligated to be parallel.

C is rejected because it is not compulsory for the chords to be perpendicular.

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RS bisects TU at Q. If TQ=5k-9 and QU=15-x
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Answer:

x = 4, TU = 22

Step-by-step explanation:

Given that TS bisects TU at Q , then

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Thus

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