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horsena [70]
3 years ago
15

I have $1500 to invest in an account that pays 1.25% compounded continuously. How much money will I have after 10 years?

Mathematics
1 answer:
S_A_V [24]3 years ago
7 0

I hope you find my answer helpful I got 39,000.

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Answer:

Hello there, please see step by step explanations to get answer.

Step-by-step explanation:

Given that:

The asset requires a capital investment of ​$100 comma 000100,000​, and MARR is 1212​% per year. Use Monte Carlo simulation and generate four trial outcomes to find its expected equivalent AW if each useful life is equally likely to occur.

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When a whole number is multiplied by 104, how does the placement of the decimal point change?
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Step-by-step explanation:


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Find the slope of the line with the given equation. Show your work.<br> 6x – 2y = 18
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Currently the equation 6x - 2y = 18 is in standard form. Convert the standard form equation into a slope-intercept form and we can find the slope easily.

Solve for y.

6x - 2y = 18
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How to tell if a scatter plot is positive or negative or no ttend?
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8 0
3 years ago
Read 2 more answers
A scientist inoculates​ mice, one at a​ time, with a disease germ until he finds 3 that have contracted the disease. If the prob
UkoKoshka [18]

Answer:

The probability that 8 mice are​ required is 0.2428.

Step-by-step explanation:

Given : A scientist inoculates​ mice, one at a​ time, with a disease germ until he finds 3 that have contracted the disease. If the probability of contracting the disease is two sevenths.

To find : What is the probability that 8 mice are​ required? The probability that that 8 mice are required is nothing ?

Solution :

Applying binomial distribution,

P(X=r)=^nC_r p^rq^{n-r}

Where, p is the probability of success p=\frac{2}{7}

q is the probability of failure q=1-p, q=1-\frac{2}{7}=\frac{5}{7}

n is total number of trials n=8

r=3

Substitute the values,

P(X=3)=^8C_3 (\frac{2}{7})^3 (\frac{5}{7})^{8-3}

P(X=3)=\frac{8!}{3!5!}\times \frac{8}{343}\times (\frac{5}{7})^{5}

P(X=3)=\frac{8\times 7\times 6}{3\times 2\times 1}\times \frac{8}{343}\times \frac{3125}{16807}

P(X=3)=0.2428

Therefore, the probability that 8 mice are​ required is 0.2428.

5 0
3 years ago
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