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uranmaximum [27]
3 years ago
7

Can you help me with this ​

Mathematics
1 answer:
marishachu [46]3 years ago
8 0

Answer:

Step-by-step explanation:

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Please hurry I will mark you brainliest.
ivann1987 [24]

Answer:

12862.83cm³

Step-by-step explanation:

Volume of the Box: [L×W×H] or [30x30x30] or [27000cm³]

Volume of the Sphere: [\frac{4}{3}\pi r^{3}] (\pi=pi=3.14) (r=radius=15) or [\frac{4}{3}×3.14×3375] or [14137.17cm³]

Volume of the empty space: 27000cm³-14137.17cm³=12862.83cm³

Btw there are online tools to help you find the volume of a sphere (just use it after you understand the equation)

Hope I helped!

4 0
3 years ago
19. answer this question.​
Irina-Kira [14]
<h3>♫ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ♫</h3>

➷ final = original x multiplier^n

n is the number of years

Substitute the values in:

final = 3800 x 1.054^3

final = 4449.440763

The closest answer is A

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

5 0
3 years ago
Read 2 more answers
Cuanto es 5X-3&gt;-2X+4
DiKsa [7]

Answer:

Step-by-step explanation:

7x > 7, o 7(x > 1).

3 0
3 years ago
Read 2 more answers
A single die is rolled twice. Find the probability of rolling an even number the first time and a number greater than 3 the seco
IceJOKER [234]

Events

• A: an even number is rolled in the first time

,

• B: a number greater than 3 is rolled the second time

The probability of rolling an even number is:

\begin{gathered} P(A)=\frac{\text{ number of favorable outcomes}}{\text{ total possible outcomes}} \\ P(A)=\frac{3}{6} \\ P(A)=\frac{1}{2} \end{gathered}

The probability of rolling a number greater than 3 is:

\begin{gathered} P(B)=\frac{\text{ number of favorable outcomes}}{\text{ total possible outcomes}} \\ P(B)=\frac{3}{6} \\ P(B)=\frac{1}{2} \end{gathered}

Events A and B are independent, then the probability of one happening after the other is:

\begin{gathered} \text{ P(A and B) = }P(A)\cdot P(B) \\ \text{ Substituting with the values previously found:} \\ \text{ P(A and B) = }\frac{1}{2}\cdot\frac{1}{2} \\ \text{ P(A and B) = }\frac{1}{4} \end{gathered}

8 0
1 year ago
Can someone tell me how to do this? <br><br>PLEASE!!!​
Schach [20]

1. 27

2. 13

hope you have a girldfriend

8 0
3 years ago
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