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denis-greek [22]
3 years ago
7

A shopping bag contains six orange juice boxes and four grape juice boxes. Without

Mathematics
1 answer:
juin [17]3 years ago
5 0

Answer:

6/25 i think

Step-by-step explanation:

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Please answer this correctly I want helping hand people to answer this correctly
crimeas [40]

Answer:

w = 36

Step-by-step explanation:

You can make a ratio 98 : 84 = 42 : w

\frac{49}{42}=\frac{42}{w}

49w = 1764

w = 36

3 0
3 years ago
Help me pls
marusya05 [52]

Answer:

the answer is 6

Step-by-step explanation:

just divide 150 by 25

5 0
3 years ago
Read 2 more answers
Plz solve i need this done today
garik1379 [7]
D,A,B,C i think this is correct !
3 0
3 years ago
Suppose you just received a shipment of nine televisions. Three of the televisions are defective. If two televisions are randoml
Temka [501]
<h2>Answer:</h2>

a)

The probability that both televisions work is:  0.42

b)

The probability at least one of the two televisions does not​ work is:

                          0.5833

<h2>Step-by-step explanation:</h2>

There are a total of 9 televisions.

It is given that:

Three of the televisions are defective.

This means that the number of televisions which are non-defective are:

          9-3=6

a)

The probability that both televisions work is calculated by:

=\dfrac{6_C_2}{9_C_2}

( Since 6 televisions are in working conditions and out of these 6 2 are to be selected.

and the total outcome is the selection of 2 televisions from a total of 9 televisions)

Hence, we get:

=\dfrac{\dfrac{6!}{2!\times (6-2)!}}{\dfrac{9!}{2!\times (9-2)!}}\\\\\\=\dfrac{\dfrac{6!}{2!\times 4!}}{\dfrac{9!}{2!\times 7!}}\\\\\\=\dfrac{5}{12}\\\\\\=0.42

b)

The probability at least one of the two televisions does not​ work:

Is equal to the probability that one does not work+probability both do not work.

Probability one does not work is calculated by:

=\dfrac{3_C_1\times 6_C_1}{9_C_2}\\\\\\=\dfrac{\dfrac{3!}{1!\times (3-1)!}\times \dfrac{6!}{1!\times (6-1)!}}{\dfrac{9!}{2!\times (9-2)!}}\\\\\\=\dfrac{3\times 6}{36}\\\\\\=\dfrac{1}{2}\\\\\\=0.5

and the probability both do not work is:

=\dfrac{3_C_2}{9_C_2}\\\\\\=\dfrac{1}{12}\\\\\\=0.0833

Hence, Probability that atleast does not work is:

             0.5+0.0833=0.5833

4 0
3 years ago
Please help!! i need this asap
kompoz [17]

I would help but I cannot read it.

3 0
3 years ago
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