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3 years ago

1. The table shows the number of men and women who have entered a grocery store.

Mathematics

2 answers:

LiRa [457]3 years ago

8 0

Answer:

4/9

Step-by-step explanation:

erik [133]3 years ago

7 0

The outcome will be 3. 4/9.

And yes, I know I'm a day late.

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Which expressions are equivalent to the given expression?

liraira [26]

$2\sqrt{10}$ is equivalent to the expression $\sqrt{40}$

entire to mixed radical:

$\sqrt{40} \\\sqrt{4\ x\ 10} \\2\sqrt{10}$

decimal value:

$2\sqrt{10}=6.32....\\\sqrt{40}=6.32...$

3 0

2 years ago

I need help please it's a math question

juin [17]

Answer:

-5/6 (negative five divided by six. the fifth option)

Step-by-step explanation:

The numerator is the first number. The denominator is the second number. Sign has to be the same and only one negative to make the fraction negative.

4 0

3 years ago

Read 2 more answers

PLEASE HELP ME I WILL GIVE BRAINLIEST!! 9 PLEASSSEEEE

olga2289 [7]

Answer:

$\frac{2}{9}$

Step-by-step explanation:

there is a four out of nine change to get a green marble

there is a 1/2 change to get heads

$\frac{4}{9}$ × $\frac{1}{2} =\frac{2}{9}$

5 0

4 years ago

I got this wrong. not sure where I went wrong

oksano4ka [1.4K]

Answer:

$\left( x-2\right)^{2} +\left( y-6\right)^{2} =12$

Step-by-step explanation:

Formula ………………………………………………………………………

The equation of a circle with center (a , b) and radius r is :

$\left( x-a\right)^{2} +\left( y-b\right)^{2} =r^{2}$

===================

Now ,let’s apply what we have learnt:

The equation of the circle with center (a , b) = (2 , 6) and radius r = 2√3 is :

$\left( x-2\right)^{2} +\left( y-6\right)^{2} =\left( 2\sqrt{3} \right)^{2}$

$\Longleftrightarrow \left( x-2\right)^{2} +\left( y-6\right)^{2} =12$

$\text{Note :} \left( 2\sqrt{3} \right)^{2} =2^{2}\times \sqrt{3}^{2} =4\times3=12$

7 0

2 years ago

Got a calc 1 question,

belka [17]

$v=\dfrac h{3x}\implies\dfrac{\mathrm dv}{\mathrm dt}=\dfrac{3x\frac{\mathrm dh}{\mathrm dt}-3h\frac{\mathrm dx}{\mathrm dt}}{3x^2}$

By the chain rule,

$\dfrac{\mathrm dh}{\mathrm dt}=\dfrac{\mathrm dh}{\mathrm dx}\dfrac{\mathrm dx}{\mathrm dt}$

We have

$h(x)=4e^{2x-6}-x^2+5\implies\dfrac{\mathrm dh}{\mathrm dx}=8e^{2x-6}-2x$

and we're given that $x$ changes at a constant rate of $\frac{\mathrm dx}{\mathrm dt}=0.2$ thousand people per minute, which means

$\dfrac{\mathrm dv}{\mathrm dt}=\dfrac{3x\left(8e^{2x-6}-2x\right)\left(0.2\frac{\text{thousand people}}{\rm min}\right)-3h\left(0.2\frac{\text{thousand people}}{\rm min}\right)}{3x^2}$

At the moment $x=4$ thousand people are in the park, we have $h(4)=4e^2-11$ , so we find

$\dfrac{\mathrm dv}{\mathrm dt}=\dfrac{12\left(8e^2-8\right)-3(4e^2-11)}{240}\dfrac{\text{thousand people}}{\rm min}=\dfrac{7(4e^2-3)}{80}\dfrac{\text{thousand people}}{\rm min}$

or approximately 2.324 thousand people per minute.

5 0

3 years ago