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Olin [163]
3 years ago
7

Determine if the given equation is a function x^2=2xy-1

Mathematics
1 answer:
devlian [24]3 years ago
5 0
Well i do say that it has to be greater than 0
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1.) p^2+14p-38=0<br> what the vertex?
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Answer:

vertex = (- 7, - 87)

Step-by-step explanation:

given a parabola in standard form : ax² + bx + c : a ≠ 0

Then the x- coordinate of the vertex is

x_{vertex} = - \frac{b}{2a}

p² + 14p - 38 is in standard form

with a = 1, b = 14, c = - 38, hence

x_{vertex } = - \frac{14}{2} = -7

substitute x = - 7 into the equation for corresponding value of y

y = (- 7)² + 14(- 7) - 38 = 49 - 98 - 38 - - 87

vertex = (- 7, - 87)


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