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8_murik_8 [283]
3 years ago
6

Which of the following, is a factor of 3x^3-9x^2+3x?

Mathematics
1 answer:
iVinArrow [24]3 years ago
3 0

Answer:

A factor of 3x^3-9x^2+3x is 1

Step-by-step explanation:

The factor of 3 are:

1,3

The factor of 9 are:

1,9,3

The factor of 2 are:

1,2

Hope this help and have a great day

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A farmer’s rectangular pen has an area of 2,700 square feet, and the width is 15 feet shorter than the length. Find the dimensio
svetoff [14.1K]

The length of the rectangle is 60 feet and the width of the rectangle is 45 feet.

<h3>What is the area of the rectangle?</h3>

Let L be the length and W be the width of the rectangle.

Then the area of the rectangle will be

Area of the rectangle = L×W square units

A farmer’s rectangular pen has an area of 2,700 square feet, and the width is 15 feet shorter than the length.

L = W + 15

Then we have

2700 = W(W + 15)

W² + 15W - 2700 = 0

W² + 60W - 45W - 2700 = 0

(W + 60)(W - 45) = 0

W = 45, -60

Then the dimension of the rectangle will be

W = 45 feet

L = W + 15

L = 45 + 15

L = 60 feet

More about the area of the rectangle link is given below.

brainly.com/question/20693059

#SPJ1

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2 years ago
If a girl cuts the grass in 3 hours and a boy cuts it in 2 hours what would be the time if they cut it toghther.?
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Answer:

d

Step-by-step explanation:

the answer is d because if you do 3+2 it equals 5 so therefore it is b

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3 years ago
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Compare the temperature change for the two masses of cold water (50 grams and 100 grams) when the same amount of hot water was a
Vesnalui [34]

Answer:

Step-by-step explanation:

All other things being equal (and there are a lot of other things) the 50 gram mass will show a larger temperature

increase than the 100 gram mass.

Why?

The formula is the same from both masses of water (50 grams and 100 grams)

The amount of heat added is the same. (Instead of using hot water, we'll a hot plate on a very low temperature but above what they are now.).

We'll leave it on until we see a rise in temperature  delta(t1) = 10 degrees

mc delta(t) = m1 * c * delta(t1)

m = 100

m1 = 50 grams.

c is going to be divided out

we'll solve for the ratio of delta(t) / delta(t1)

100 * delta(t) = 50 (delta(t1)

100 * delta(t) = 50*10

delta(t) = 50*10/100

delta(t) = 5 degrees.

Though this may look rather convoluted, the result is telling us is that delta(t1) for the 50 gram mass is twice as big as as for the 100 gram mass.

The 100 gram mass only rises 5 degrees.

The 50   gram mass rises 10 degrees.

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