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2 years ago

Y = f(x) = 4^x Find f(x) when x = 1/2 Enter the correct answer.

Mathematics

2 answers:

strojnjashka [21]2 years ago

7 0

We have

$f(x)=4^x$

We want to know what is the value of y when x is 1/2

$f(\frac{1}{2})=4^{\frac{1}{2}}$

Note that $a^{\frac{b}{c}}=\sqrt[c]{a^b}$ hence

$f(\frac{1}{2})=4^{\frac{1}{2}}=\sqrt[2]{4^1}=\boxed{2}$

Hope this helps.

nirvana33 [79]2 years ago

4 0

I believe the answer is 2

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Solve the equation for x, where x is a real number (5 points): <br> -2x^2 + 5x - 10 = 3

KatRina [158]

Subtract 3 from both sides so that the equation becomes -2x^2 + 5x - 13 = 0.
To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0
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                                      x = [ -5 ± √((5)^2 - 4(-2)(-13)) ] / ( 2(-2) )
                                      x = [-5 ± √(25 - (104) ) ] / ( -4 )
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2 years ago

8. Is the following statement true or false? Justify your conclusion. If a and b are nonnegative real numbers and a + b =0, then

atroni [7]

Answer:

If $a + b = 0$ then $a = 0$ and $b =0$

a | b | a + b (answer)

0 | 0 | 0

0 | 1 | 1

0 | 2 | 2

1 | 0 | 1

2 | 0 | 2

1 | 1 | 2

2 | 1 | 3

Step-by-step explanation:

Considering the following conditions for the real numbers:

$a\geq 0\\b\geq 0$

Following the rules of these in-equations, it is possible to deduce:

$a + b \geq 0$

Then, if the proposed statement is:

$a + b = 0$

The conditions above shall comply the requirements established, but first, analyzing the statement:

If $a \geq 0$ and $b \geq 0$ then $a + b \geq a$ , $a + b \geq b$ and $a + b \geq 0$ .

If $a = 0$ and b a non negative real number, then $a + b \geq b$ , but because to $a = 0$ , then $a + b = b$ . Due to the commutative property of sums, the same behavior will be presented if $b = 0$ and a a non negative real number.