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Over [174]
3 years ago
6

Y = f(x) = 4^x Find f(x) when x = 1/2 Enter the correct answer.

Mathematics
2 answers:
strojnjashka [21]3 years ago
7 0

We have

f(x)=4^x

We want to know what is the value of y when x is 1/2

f(\frac{1}{2})=4^{\frac{1}{2}}

Note that a^{\frac{b}{c}}=\sqrt[c]{a^b} hence

f(\frac{1}{2})=4^{\frac{1}{2}}=\sqrt[2]{4^1}=\boxed{2}

Hope this helps.

nirvana33 [79]3 years ago
4 0
I believe the answer is 2
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AB=25 , BD=4, Solve for the radius?<br> Please help!!!!!
Alex787 [66]

9514 1404 393

Answer:

  r = 14.5

Step-by-step explanation:

AD is the perpendicular bisector of chord EC, so is the diameter of the circle. The radius is half the diameter.

  r = AD/2 = (AB +BD)/2 = (25 +4)/2 = 29/2

  r = 14.5

__

Segments BE and BC are 10 = √(25·4)

4 0
2 years ago
6(x² + 2x + 7)pls ans​
Kazeer [188]

Answer:

Use distributive property

3 0
3 years ago
Complete the problem to represent the situation given by the equation 0.40e + 10 + 15 = 0.20e + 5 + 25. At one store a trophy co
olganol [36]

Answer: The number of letters that must be engraved for the costs to be the same is 125.

Step-by-step explanation:

Since we have given that

0.4e+10+15=0.20e+5+25

We need to find the number of letters.

0.4e+25=0.2e+30\\\\0.4e-0.2e=30-25\\\\0.2e=25\\\\e=\dfrac{25}{0.2}\\\\e=125

Hence, the number of letters that must be engraved for the costs to be the same is 125.

8 0
3 years ago
Read 2 more answers
How many sunsets of at least one element does a set of six elements have
Lesechka [4]

Answer:

63

Step-by-step explanation:

Given:

a set of six elements  

The solution would be like this for this specific problem:

number of subsets of n elements = 2^n

(2^6) - 1

= 64 – 1

= 63

7 0
3 years ago
A powerful computer is purchased for $2000, but loses 20% of its value each year. How much will it be worth 4 years from now?
Jet001 [13]

Answer:

(A)Decay

(b)0.8

(c)First Term

(d)f(t)=2000(0.8)^t

(e)$819.20

Step-by-step explanation:

The exponential function for modelling growth or decay is given as:

A(t)=A_o(1\pm r)^t,

Where:

Plus indicates growth and minus indicates decay.

A_o$ is the Initial Value\\r is the growth/decay rate\\t is the time period

For a powerful computer that was purchased for $2000, but loses 20% of its value each year.

(a)Since it loses value, it is a decay.

(b)Multiplier

Its value decays by 20%.

Therefore, our multiplier(1-r) =(1-20&)=1-0.2

Multiplier =0.8

(c)$2000 is our First term (or Initial Value A_o)

(d)The function for this problem is therefore:

f(t)=f_o(1- r)^t\\f(t)=2000(1- 0.2)^t\\\\f(t)=2000(0.8)^t

(e)Since we require the worth of the computer after 4 years,

t=4 years

f(4)=2000(0.8)^4\\f(4)=\$819.20

6 0
3 years ago
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