A group of children share 11 3/7 vegetarian pizzas. Each child receives 10/14 of a pizza. How many children are in the group

A bag contains 4 red balls, 2 green balls, 3 yellow balls, and 5 blue balls. Find each probability for randomly removing balls w

AfilCa [17]

Answer:

$\frac{15}{4802}$ , $\frac{15}{9604}$ , $\frac{9}{2401}$ , $\frac{9}{4802}$

Step-by-step explanation:

The bag has a total of (4+2+3+5) = 14 balls. Set up the proportions:

Red: $\frac{4}{14}$

green: $\frac{2}{14}$

yellow: $\frac{3}{14}$

blue: $\frac{5}{14}$

Now solve!

Removing 1 yellow, 1 red, 1 green, and 1 blue = $\frac{3}{14} \cdot \frac{4}{14} \cdot \frac{2}{14} \cdot \frac{5}{14} =\frac{15}{4802}$

Removing 1 blue, 1 green, 1 green, and 1 yellow = $\frac{5}{14} \cdot \frac{2}{14} \cdot \frac{2}{14} \cdot \frac{3}{14} =\frac{15}{9604}$

Removing 1 red, 1 red, 1 yellow, and 1 yellow = $\frac{4}{14} \cdot \frac{4}{14} \cdot \frac{3}{14} \cdot \frac{3}{14} =\frac{9}{2401}$

Removing 1 green, 1 yellow, 1 yellow, and 1 red = $\frac{2}{14} \cdot \frac{3}{14} \cdot \frac{3}{14} \cdot \frac{4}{14} =\frac{9}{4802}$

4 0

2 years ago

Explain the level of uncertainties involve in concept of probability. The next generation of miniaturized wireless capsules with

RUDIKE [14]

Answer:

a) the probability that Both motors will operate satisfactorily in the capsule 0.6222

b) the probability that One motor will operate satisfactorily and the other will not is 0.3556

Step-by-step explanation:

Given that;

total number of motors N = 10

number of motors will not operate satisfactory m = 2

number of motors randomly selected n = 2

let X be number of motors will that will not operate successfully

here, X≅Hyper geometric (x; N,n,m)

The probability mass function of x is;

P (X = x)= { m } {N - m }

{x } {n - x}

⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻

{ N }

{ n }

a)

the probability that both motors will operate satisfactorily in the capsule i.e no motor will not operate satisfactory

so

P(X= 0) = { 2 } { 10 - 2 }

{0 } { 2 - 0}

⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻

{ 10 }

{ 2 }

so

P (X = 0) = { 2 } { 8}

{ 0 } { 2 }

⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻

{ 10 }

{ 2 }

p(P= 0)=1×28 / 45 = 28/45 = 0.6222

Therefore the probability that Both motors will operate satisfactorily in the capsule 0.6222

b)

the probability that one motor will operate satisfactorily and the other will not.

P(X=1) = { 2 } { 10 - 2 }

{ 1 } { 2 - 1 }

⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻

{ 10 }

{ 2 }

so

P(X=1) = { 2 } { 8 }

{ 1 } { 1 }

⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻

{ 10 }

{ 2 }

P(X=1) = 2×8 / 45 = 16/45 = 0.3556

Therefore the probability that One motor will operate satisfactorily and the other will not is 0.3556

3 0

3 years ago

I’m confused can ya help me

Harlamova29_29 [7]

Answer:

C & D

Step-by-step explanation:

x² + 3x - 3 = 0

a = co efficient of x² = 1

b= co efficient of x = 3

c = constant = -3

roots = (-b ± $\sqrt{b-4ac}$ )/2a

= (-3± $\sqrt{3^{2}-4*1*[-3]}$ )/2*1

= (-3± $\sqrt{9+12}$ )/2

= (-3±√21)/2

$x = \frac{-3+\sqrt{21}}{2} ; x =\frac{-3-\sqrt{21}}{2}$

7 0

3 years ago

A company with n employees publishes an internal calendar, where each day lists the employees having a birthday that day. What i

lutik1710 [3]

Answer: $1-(\frac{364}{365})^n$

Step-by-step explanation:

Binomial probability formula :-

$P(x)=^nC_xp^x(1-p)^x$ , where P(x) is the probability of getting success in x trials, n is the total number of trials and p is the probability of getting success in each trial.

We assume that the total number of days in a particular year are 365.

Then , the probability for each employee to have birthday on a certain day :

$p=\dfrac{1}{365}$

Given : The number of employee in the company = n

Then, the probability there is at least one day in a year when nobody has a birthday is given by :-

$P(x\geq1)=1-P(x$

Hence, the probability there is at least one day in a year when nobody has a birthday = $1-(\frac{364}{365})^n$

5 0

3 years ago

Which number shows 460,593 rounded to the nearest hundred thousand?

Mariulka [41]

Your answer is C. 500,000

4 0

3 years ago