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Dafna1 [17]
2 years ago
5

Solve for c. 4(c + 1) = 16

Mathematics
1 answer:
MariettaO [177]2 years ago
8 0

Answer:c=4

Step-by-step explanation:

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What is the domain of the function y=in(x+2) x<-2 x>-2 x<2 x> x<-2 x>-2 x<2 x>2
aev [14]

For this case we must find the domain of the following function:

y = ln (x + 2)

By definition, the domain of a function is given by all the values for which the function is defined.

In this case, the argument of the expression must be greater than 0 to be defined.

x + 2> 0\\x> -2

Thus, the domain of the function is given by all the values of x greater than -2.

Answer:

Domain: x> -2

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3 years ago
Determine if the function is one-to-one.<br><br>​
olya-2409 [2.1K]

Answer:

No

Step-by-step explanation:

From what I saw on google for what "one to one" means, It's basically meaning that the bottom of that quadratic function is at point (0 , 0) and hits both (-1 , 1) and (1 , 1) on the graph.

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3 years ago
You and your friend mix water and citric acid. You add 3 cups of citric acid for every 16 cups of water. Your friend adds 2 cups
Viktor [21]

Answer:

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Your friend: if it was 4 cups it’d be 12 water

Step-by-step explanation:

I believe your friends is more acidic because your Is being diluted more

4 0
2 years ago
3. if kx² + 2x + k = -kx have equal roots, find the values of k.<br>​
crimeas [40]

Answer:

k = - \frac{2}{3} , k = 2

Step-by-step explanation:

Using the discriminant Δ = b² - 4ac

The condition for equal roots is b² - 4ac = 0

Given

kx² + 2x + k = - kx ( add kx to both sides )

kx² + 2x + kx + k = 0 , that is

kx² + (2 + k)x + k = 0 ← in standard form

with a = k, b = 2 + k and c = k , thus

(2 + k)² - 4k² = 0 ← expand and simplify left side

4 + 4k + k² - 4k² = 0

- 3k² + 4k + 4 = 0 ( multiply through by - 1 )

3k² - 4k - 4 = 0 ← in standard form

(3k + 2)(k - 2) = 0 ← in factored form

Equate each factor to zero and solve for k

3k + 2 = 0 ⇒ 3k = - 2 ⇒ k = - \frac{2}{3}

k - 2 = 0 ⇒ k = 2

5 0
3 years ago
How many digits do i have to write for scientific notation?
butalik [34]
All significant digits...
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