100 * ( 4 / 100 ) * ( 26 / 12 ) = 4 * ( 26 / 12 ) = 26 / 3 = $ 8.66 ;
6x plus 3x plus 4 minus 2
E) sqrt(30)
This is a nice problem. It was helpful to read the topic at the top.
Notice that the two right triangles are similar. Their sides are in proportion.
That is the side '3' is what 'x' is in the other triangle (you need to rotate it!)
Then 'x' is similar to '10'
3/x=x/10 ---> x^2=30, x=sqrt(30)
If you are patient, you can check that for sqrt(30) pythagoras theorem works for all the triangles.
Best
Then
K² + 13k + 30 = 0
This is a quadratic equation. Let's attempt solving it by factorization.
Coefficient of k² = 1, last term = 30
Multiply these two together 1*30 = 30
We think of two numbers that multiply to give 30 and add to give the middle term 13.
The two numbers are 3 and 10.
3*10 = 30, 3 + 10 = 13.
we replace the 13k with 3k + 10k
k² + 13k + 30 = 0
k² + 3k + 10k + 30 = 0
k(k + 3) + 10(k + 3) = 0
(k + 3)(k + 10) = 0
(k + 3) = 0 or (k + 10) = 0
k = 0 - 3 or k = 0 - 10
k = -3, or -10
I hope this helps.
Okay the height would be nice if it would have to come
