Question

The solutions to (x + 4) ^2- 2 = 7 are​

Answer 1

Answer:

x = -1, -7

Step-by-step explanation:

$(x+4)^2$ -2 = 7

$(x+4)^2$ -9 = 0 (Taking 7 to the other side)

$(x+4)^2$ - $3^2$ = 0

Now use the difference of two squares rule

[((x+4)+3).((x+4)-3)] = 0

[(x+7).(x+1)] = 0

Now solve for x

x = -1, -7