3(x+6)=2(4x+14) what is the value of x?
2 answers:
Hi there! ~
So to start off, we are trying to find the value of x. This is a lot different then just "replacing x with the given value" as we have previously done. So lets get started ~
• Our first step is going to be to distribute our problem.
We have; (Putting these in parenthesis)
3(x+6) = 2(4x + 14)
↓ ↓ ↓ ↓ ↓ ↓
(3)(x) + (3)(6) = (2))4x) + (2)(14)
↓ ↓ ↓ ↓ ↓ ↓
3x + 18 = 8x + 26
• Now we need to subtract "18" by both sides of the given equation.
-5x + 18 - 18 = 28 - 18
28-18 = 10
-5x = 10
↓ ↓ ↓ ↓ ↓
• Now we need to divide both of our sides by -5, to get our final and foremost answer.
And with that we get our final answer; x = -2
So to start off, we are trying to find the value of x. This is a lot different then just "replacing x with the given value" as we have previously done. So lets get started ~
• Our first step is going to be to distribute our problem.
We have; (Putting these in parenthesis)
3(x+6) = 2(4x + 14)
↓ ↓ ↓ ↓ ↓ ↓
(3)(x) + (3)(6) = (2))4x) + (2)(14)
↓ ↓ ↓ ↓ ↓ ↓
3x + 18 = 8x + 26
• Now we need to subtract "18" by both sides of the given equation.
-5x + 18 - 18 = 28 - 18
28-18 = 10
-5x = 10
↓ ↓ ↓ ↓ ↓
• Now we need to divide both of our sides by -5, to get our final and foremost answer.
And with that we get our final answer; x = -2
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Step-by-step explanation:
I've posted solutions in the picture. Rather the ways to solve them. Check and find answers on your own.
Also, I've not solved the problem by differential calculus. You can, obviously, if you're interested. Use it for ease and for tougher equations.
Answer:
Probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.
Step-by-step explanation:
We are given that the number of hours spent studying the week before final exams was normally distributed with mean 25 and standard deviation 15.
A sample of 36 students was selected.
<em>Let </em><em> = sample average time spent studying</em>
The z-score probability distribution for sample mean is given by;
Z = ~ N(0,1)
where, = population mean hours spent studying = 25 hours
= standard deviation = 15 hours
n = sample of students = 36
The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.
Now, Probability that the average time spent studying for the sample was between 29 and 30 hours studying is given by = P(29 hours < < 30 hours)
P(29 hours < < 30 hours) = P(
< 30 hours) - P(
29 hours)
P( < 30 hours) = P(
<
) = P(Z < 2) = 0.97725
P(
29 hours) = P(
) = P(Z
1.60) = 0.94520
<em>So, in the z table the P(Z </em><em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2 and x = 1.60 in the z table which has an area of 0.97725 and 0.94520 respectively.</em>
Therefore, P(29 hours < < 30 hours) = 0.97725 - 0.94520 = 0.0321
Hence, the probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.