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NeTakaya
3 years ago
5

What is the principal square root of -4

Mathematics
1 answer:
devlian [24]3 years ago
6 0

Answer:

The principal square root of -4 is 2i.

Step-by-step explanation:

\sqrt{-4} = 2i

We have the following steps to get the answer:

Applying radical rule \sqrt{-a} =\sqrt{-1} \sqrt{a}

We get \sqrt{-4} =\sqrt{-1} \sqrt{4}

As per imaginary rule we know that \sqrt{-1}=i

= \sqrt{4} i

Now \sqrt{4} =2

Hence, the answer is 2i.

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Find the value of k and x2<br> x^2+ 13x + k = 0, x1=-9
Anarel [89]

Given:

The quadratic equation is:

x^2+13x+k=0

x_1=-9

To find:

The value of k and x_1.

Solution:

We have,

x^2+13x+k=0                ...(i)

Putting x=-9, we get

(-9)^2+13(-9)+k=0

81-117+k=0

-36+k=0

k=36

Putting k=36 in (i), we get

x^2+13x+36=0

Splitting the middle term, we get

x^2+9x+4x+36=0

x(x+9)+4(x+9)=0

(x+9)(x+4)=0

x=-9,-4

Here, x_1=-9 and x_2=-4.

Therefore, the required values are k=36 and x_2=-4.

3 0
2 years ago
A solution's temperature increased 11.3°C in 5 minutes. What was the average temperature increase per minute? Answer: _______ °C
sertanlavr [38]

Answer:

2.26° per minute

Step-by-step explanation:

11.3 / 5

7 0
2 years ago
Use y=2.5x+65 to find x when y=75
uranmaximum [27]

Answer:

The value of x is 4

Step-by-step explanation:

y = 2.5x + 65; y = 75

Now, Substitute

y = 2.5x + 65

75 = 2.5x + 65

75 – 65= 2.5x + 65 – 65

10 = 2.5x

2.5x = 10

2.5x/2.5 = 10/2.5

x = 4

Thus, The value of x is 4

 

<u>-TheUnknownScientist</u><u> 72</u>

6 0
2 years ago
Which of the following is a factor of 3x^3-12x?<br> 3x-4<br><br> x+2<br><br> x+3<br><br> x-4
VMariaS [17]

Answer:

x + 2

Step-by-step explanation:

3x^3 - 12x

=3x(x^2 - 4)

= 3x(x + 2)(x - 2)

so (x+2), (x - 2) and 3x are the factors of 3x^3 - 12x

answer:

x + 2

6 0
3 years ago
Read 2 more answers
Find the volume of a cylinder with radius 5.7cm and height 10 cm, correct to 1 decimal place​
Veseljchak [2.6K]

\textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=5.7\\ h=10 \end{cases}\implies \begin{array}{llll} V=\pi (5.7)^2(10)\implies V=324.9\pi \\\\\\ V\approx 1020.7 \end{array}

8 0
2 years ago
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