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3 years ago

What is the principal square root of -4

Mathematics

1 answer:

devlian [24]3 years ago

6 0

Answer:

The principal square root of -4 is 2i.

Step-by-step explanation:

$\sqrt{-4}$ = 2i

We have the following steps to get the answer:

Applying radical rule $\sqrt{-a} =\sqrt{-1} \sqrt{a}$

We get $\sqrt{-4} =\sqrt{-1} \sqrt{4}$

As per imaginary rule we know that $\sqrt{-1}=i$

= $\sqrt{4} i$

Now $\sqrt{4} =2$

Hence, the answer is 2i.

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Determine the value of c that will result in a perfect square trinomial. <br> w^2+6w+ c =130+c

Genrish500 [490]

Answer:

The value of c that will result in a perfect square trinomial is (3)^2 or 9

The perfect square trinomial is: $(w+3)^2=139$

Step-by-step explanation:

We need to determine the value of c that will result in a perfect square trinomial.

$w^2+6w+ c =130+c$

Perfect square trinomial are of form: $a^2+2ab+b^2=(a+b)^2$

Now, the equation given is:

$w^2+6w+ c =130+c$

Looking at the term 6w, we can write it as 2(w)(3)

We are given: a = w, 2ab = 2(w)(3) so, b will be: (3)^2

So, we will be adding (3)^2 on both sides

$w^2+6w+ c=130+c\\w^2+2(w)(3)+ (3)^2 =130+(3)^2\\The\:left\:side\:becomes: a^2+2ab+b^2\\We\:can\:write\:it\:as: (a+b)^2\\We\:have\:a=w\: and\: b=3\\(w+3)^2=130+9\\(w+3)^2=139$

So, The value of c that will result in a perfect square trinomial is (3)^2 or 9

The perfect square trinomial is: $(w+3)^2=139$

3 0

3 years ago

Which number produces an irrational number when multiplied by -1.25?

Salsk061 [2.6K]

A possible answer is $\pi$ .

Pi is an irrational number and when you multiply a rational number with an irrational number, you end up with an irrational number.

5 0

3 years ago

Find the point B on AC such that the ratio of AB to BC is 2:3

Virty [35]

Answer:

B(4, - 3 )

Step-by-step explanation:

We have A(2, - 7) and C(7, 3 )

Using the section formula to calculate the coordinates of B

$x_{B}$ = $\frac{3(2)+2(7)}{2+3}$ = $\frac{6+14}{5}$ = $\frac{20}{5}$ = 4