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Kruka [31]
3 years ago
15

What is the area of this rectangle? Provide supportive evidence so I can learn better about this. I’m having troubles.

Mathematics
1 answer:
Katyanochek1 [597]3 years ago
4 0

Answer:

the answer is 15x^8 y^3

Step-by-step explanation:

the area of a rectangle is length times width right? this means you have to multiply the values that represent the length and width. in this case those values would be 5x^6 y^2 and 3x^2 y

step 1. set up your problem

it should look like this:

(5x^6 y^2)(3x^2 y)

step 2. multiply the values with corresponding variables

first, x values

(5x^6)(3x^2)

5×3=15 and x^6 × x^2=x^8 when multiplying exponents you add the powers the numbers are raised to. in this case 6+2=8

you should end up with 15x^8

next, y values

y^2 + y

remember what i said about multiplying exponents? you just add the power the variables are raised to. in this case, 2 and 1. when their is no exponent we just add a 1. so, 2+1=3

you end up with y^3

lastly, combine

15x^8 + y^3 = 15x^8y^3

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3 years ago
Rewrite the indicated real nth root(s) of a in radical form
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Answer:

\sqrt[n]{a}

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2. \sqrt[4]{16} = \sqrt[4]{2^4} = 2

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3 years ago
The slope of the line below is 2. Write a point-slope equation of the line using the coordinates of the labeled point( 3,10)
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Answer:

Point slope form of the line is  y-10=2(x-3)


Step-by-step explanation:

The point-slope form of a line is given as:

y-y_1=m(x-x_1)

Where,

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<em>The question tells us the slope is 2, hence m=2 and the point given is (3,10) which means x_1=3 and y_1=10. Substituting these values into the </em><em>point slope form of a line </em><em>gives us:</em>

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Hence, point slope form of the line is  y-10=2(x-3)


8 0
3 years ago
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