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3 years ago

8

Jose needs to make a total of 25 deliveries this week. So far he has completed 15 of them. What percentage of his total deliveri

es has Jose completed?

1 answer:

schepotkina [342]3 years ago

7 0

Answer:

Jose has completed <u>60%</u> of his total deliveries.

Step-by-step explanation:

Given:

Jose needs to make a total of 25 deliveries this week. So far he has completed 15 of them.

Now, to find the percentage of his total deliveries has Jose completed.

Total deliveries = 25.

Deliveries completed = 15.

Now, to get the percentage of his total deliveries has Jose completed:

$\frac{Deliveries\ completed}{Total\ deliveries} \times 100$

$=\frac{15}{25} \times 100$

$=0.6\times 100$

$=60\%.$

Therefore, Jose has completed 60% of his total deliveries.

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How many solutions does the equation have, x1 + x2 + x3 = 10 , where x1 , x2, and x3 are non-negative integers?

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Non-negative integers are positive integers or zero.

1. When $x_1=0,$ then there are such possible cases for $x_2$ and $x_3:$

$x_2=0,\ x_3=10;$
$x_2=1,\ x_3=9;$
$x_2=2,\ x_3=8;$
$x_2=3,\ x_3=7;$
$x_2=4,\ x_3=6;$
$x_2=5,\ x_3=5;$
$x_2=6,\ x_3=4;$
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In total 11 solutions for $x_1=0.$

2. For $x_1=1,$ there are such possible cases for $x_2$ and $x_3:$

$x_2=0,\ x_3=9;$
$x_2=1,\ x_3=8;$
$x_2=2,\ x_3=7;$
$x_2=3,\ x_3=6;$
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$x_2=6,\ x_3=3;$
$x_2=7,\ x_3=2;$
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In total 10 solutions for $x_1=1.$

3. This process gives you

for $x_1=2$ - 9 solutions;
for $x_1=3$ - 8 solutions;
for $x_1=4$ - 7 solutions;
for $x_1=5$ - 6 solutions;
for $x_1=6$ - 5 solutions;
for $x_1=7$ - 4 solutions;
for $x_1=8$ - 3 solutions;
for $x_1=9$ - 2 solutions;
for $x_1=10$ - 1 solution.

4. Add all numbers of solutions:

$11+10+9+8+7+6+5+4+3+2+1=66.$

Answer: there are 66 possible solutions (with non-negative integer variables)

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