Answer:
cos(u) and sin(u) can be expanded in with a Maclaurin series, and cos(c) and sin(c) are constants.
Step-by-step explanation:
thats it
The minute hand is like an eight inch radius of a circle, whose circumference would equal 2 * PI * 8 = 50.265 inches. By moving to 8 o'clock, it travels 2/3 of the circumference or 50.265 * 2/3 = 33.510 inches
Pairs which is Adjacent side for quadrilateral MOLE is given below.
Step-by-step explanation:
Given:
Quadrilateral MOLE
Pair of adjacent sides of the quadrilateral.
Adjacent sides have one vertex common.
Option A: MO and LE
These sides does not have common vertex.
MO and LE are opposite sides in the quadrilateral MOLE.
It is not true.
Option B: EO and ME
In the quadrilateral, ME is not a side.
So it is not true.
Option C: LE and OL
In the quadrilateral, OL is not a side.
So it is not true.
Option D: ML and LE
These sides have common vertex L.
Therefore ML and LE are pair of adjacent sides.
It it true.
Hence ML and LE is a pair of adjacent side for quadrilateral MOLE.
Answer:
A. 2⅓ and D.1
Step-by-step explanation:
We are required to select the values of x that makes the inequality x>½ true.
A. 2⅓
B. 0
C.-1½
D. 1
E.-¾
Options C and E are negative numbers and are therefore less than the positive number ½.
Option B(i.e. 0) is also less than ½ or 0.5 and therefore do not satisfy the inequality given.
Options A and D are greater than ½ and therefore satisfies the inequality given.
Check the picture below.
well, we want only the equation of the diametrical line, now, the diameter can touch the chord at any several angles, as well at a right-angle.
bearing in mind that <u>perpendicular lines have negative reciprocal</u> slopes, hmm let's find firstly the slope of AB, and the negative reciprocal of that will be the slope of the diameter, that is passing through the midpoint of AB.
![\bf A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{1}}}\implies \cfrac{-3}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{slope of AB}}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{\textit{\underline{negative reciprocal} and slope of the diameter}}{\cfrac{4}{3}}](https://tex.z-dn.net/?f=%5Cbf%20A%28%5Cstackrel%7Bx_1%7D%7B1%7D~%2C~%5Cstackrel%7By_1%7D%7B4%7D%29%5Cqquad%20B%28%5Cstackrel%7Bx_2%7D%7B5%7D~%2C~%5Cstackrel%7By_2%7D%7B1%7D%29%20~%5Chfill%20%5Cstackrel%7Bslope%7D%7Bm%7D%5Cimplies%20%5Ccfrac%7B%5Cstackrel%7Brise%7D%20%7B%5Cstackrel%7By_2%7D%7B1%7D-%5Cstackrel%7By1%7D%7B4%7D%7D%7D%7B%5Cunderset%7Brun%7D%20%7B%5Cunderset%7Bx_2%7D%7B5%7D-%5Cunderset%7Bx_1%7D%7B1%7D%7D%7D%5Cimplies%20%5Ccfrac%7B-3%7D%7B4%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bslope%20of%20AB%7D%7D%7B-%5Ccfrac%7B3%7D%7B4%7D%7D%5Cqquad%20%5Cqquad%20%5Cqquad%20%5Cstackrel%7B%5Ctextit%7B%5Cunderline%7Bnegative%20reciprocal%7D%20and%20slope%20of%20the%20diameter%7D%7D%7B%5Ccfrac%7B4%7D%7B3%7D%7D)
so, it passes through the midpoint of AB,
so, we're really looking for the equation of a line whose slope is 4/3 and runs through (3 , 5/2)
