Question

A loaded grocery cart is rolling across a parking lot in a strong wind. You apply a constant force F⃗ =( 35 N )i^−( 37 N )j^ to the cart as it undergoes a displacement s⃗ =(− 8.7 m )i^−( 3.1 m )j^. Part A How much work does the force you apply do on the grocery cart? Express your answer using three significant figures.

Answer 1

Answer:

-189.8 J

Step-by-step explanation:

We are given that f

Force applied=F=35 Ni-37 Nj

Displacement, s=(-8.7m)i-(3.1m)j

We have to find the work done .

We know that

Work done=$F\cdot s$

Using the formula

Work done=$(35i-37j)\cdot (-8.7-3.1)$

Work done=$-304.5+114.7$

Using $i\cdot i=j\cdot j=k\cdot k=1,i\cdot j=j\cdot i=j\cdot k=k\cdot j=i\cdot k=k\cdot i=0$

Work done=-189.8J

Hence, the work done =-189.8 J