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Fantom [35]
3 years ago
11

Lyle shot three times as many baskets as cliff, while kyle shot 12 more baskets than cliff. if lyle and kyle shot the same numbe

r of baskets, how many baskets did each of them shoot?
Mathematics
1 answer:
olga_2 [115]3 years ago
5 0
12x3=36 its that simple m8
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What is the mode of the following numbers?<br> 3,7, 5, 2, 5, 5, 2,5
tangare [24]

The mode is 5.ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

8 0
3 years ago
Read 2 more answers
Suzan sees a bag of marbles, she grabs a handful at random. She has seen a bag containing four red marbles, four green ones, two
Rainbow [258]
The answer to this question would be: 85/99

In this question, Suzan is taking 8 marble from a bag containing 4 red marbles, 4 green ones, 2 white ones, and 2 purple ones. The total marble in the bag should be: 4+4+2+2= 12. The question is how much the probability to get <4 red marble. In this question, the green, white and purple is not specified so you can join them into not red group. It will be easier to find the probability of "have all the red one" which mean Suzan take 4 red marble and 4 not-red marble<span>

Ways to take 8 marble out of 12=12C5= 12!/4!8!= </span>495
Ways to take 4 red marble out of 4= 4C4= 1
Ways to take 4 not red marble out of 8= 8C4= 8!/4!4!= 70

Probability to <span>have all the red ones= 1*70/495= 14/99
</span>Then the probability does not have all the red ones= 99/99 - 14/99= 85/99
6 0
3 years ago
(1 point) A bucket that weighs 3.6 pounds and a rope of negligible weight are used to draw water from a well that is 78 feet dee
Deffense [45]

Answer:

The total work done in pulling the bucket to the top of the well is approximately 3,139.1 ft·lb

Step-by-step explanation:

The given parameters are;

The mass of the bucket, W = 3.6 pounds

The depth of the well, h = 78 feet deep

The mass of water in the bucket = 38 ponds

The rate at which the water is pulled up = 2.9 feet per second

The rate at which water is leaking from the bucket, \dot m = 0.1 pounds per second

We separate and find the work done for lifting the bucket and the water individually, then we add the answers to get the solution to the question as follows;

The work done in lifting bucket empty from the well bottom, W_b = W × h

∴  W_b = 3.6 pounds × 78 feet = 280.8 ft-lb

The work done in lifting bucket empty from the well bottom, W_b = 280.8 ft-lb

The time it takes to lift the bucket from the well bottom to the top, 't', is given as follows;

Time, t = Distance/Velocity

The time it takes to pull the bucket from the well bottom is therefore;

t = 78 ft./(2.9 ft./s) ≈ 26.897

The time it takes to pull the bucket from the well bottom to the top, t ≈ 26.897 s

The mass of water that leaks out from the bucket before it gets to the top, m₂, is therefore;

m₂ = \dot m × t

∴ m₂ = 0.1 lbs/s × 26.897 s = 2.6897

The mass of the water that leaks, m₂ = 2.6897 lbs

The mass of water that gets to the surface m₃ = m - m₂

∴ m₃ = 38 lbs  - 2.6897 lbs ≈ 35.3103 lbs

Given that the water leaks at a constant rate the equation representing the mass of the water as it is lifted can b represented by a straight line with slope, 'm' given as follows;

The slope of the linear equation m = (38 lbs - 35.3103 lbs)/(78 ft. - 0 ft.) = 0.03448\overline 3 lbs/ft.

Therefore, the equation for the weight of the water 'w' can be expressed as follows;

w = 0.03448\overline 3·y + c

At the top of the well, y = 0 and w = 38

∴ 35.3103 = 0..03448\overline 3 × 0 + c

c = 35.3103

∴ w = 0.03448\overline 3·y + 35.3103

The work done in lifting the water through a small distance, dy is given as follows;

(0.03448\overline 3·y + 38) × dy

The work done in lifting the water from the bottom to the top of the well, W_{water}, is given as follows;

W_{water} = \int\limits^{78}_0 {0.03448\overline 3 \cdot y + 35.3103 } \, dy

\therefore W_{water} = \left [ {\dfrac{0.03448\overline 3 \cdot y^2}{2}   + 35.3103 \cdot y\right ]^{78}_0

W_{water} = (0.034483/2 × 78^2 + 35.3103 × 78) - (0.034483 × 0 + 38 × 0)  ≈ 2,859.1

The work done in lifting only the water, W_{water} ≈ 2,859.1 ft-lb

The total work done, in pulling the bucket to the top of the well, W = W_b + W_{water}

∴ W = 2,859.1 ft.·lb + 280.8 ft.·lb ≈ 3,139.1 ft·lb

The total work done, in pulling the bucket to the top of the well, W ≈ 3,139.1 ft·lb.

6 0
3 years ago
Please find the missing side of the triangle and round the answer to the nearest tenth. Thanks.
SashulF [63]

Answer:

39.6

Step-by-step explanation:

Given in the right angled triangle above are:

Ѳ = 49°,

Adjacent length = 26

Hypotenuse length = x

To find x in the right angled triangle given above, apply the trigonometric formula, cos Ѳ = adjacent length/hypotenuse length

Thus,

cos(49) = \frac{26}{x}

Multiply both sides by x

cos(49)*x = \frac{26}{x}*x

cos(49)*x = 26

0.6561*x = 26

Divide both sides by 0.6561 to find x

\frac{0.6561*x}{0.6561} = \frac{26}{0.6561}

x = \frac{26}{0.6561}

x = \frac{26}{0.6561}

x = 39.63

x = 39.6 (to nearest tenth)

8 0
3 years ago
Find the area of a regular polygon
Dimas [21]

Answer:

(N-2)x180=sum of interior angles

So (5-2)x180=540

Divided by number of sides=540/4=108... then each angle is 108 divide to triangles ..so they will have 2 angles =54 2 sides =4 the last angle =72 ."of the triangle " area of triangle =1/2xsxsxsin(side in

between)

So 1/2x4x4xsin(72)= then multiply it by 5 as u will have 5 triangles .. so it will be 190.2(probably i tried)

Step-by-step explanation:

4 0
3 years ago
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