9514 1404 393
Answer:
(c) CPCTC
Step-by-step explanation:
The proof might go something like this:
- EH ≅ KH, FH ≅ JH . . . . . given
- ∠EHF ≅ ∠KHJ . . . . . vertical angles are congruent
- ∆EHF ≅ ∆KHJ . . . . . SAS congruence theorem
- EF ≅ KJ . . . . . CPCTC
Note that JK is an alternate name for segment KJ. We used KJ in the proof because vertices K and J correspond directly to vertices E and F in the congruent triangles.
V= 1/3 LWH
1/3(3.5)(3.5)(4.7)
19.19 in ^3
SA= 2(3.5)(5.2)+(3.5)^2
48.65 in^2
Answer:
D(5,-8)
Step-by-step explanation:
The given point is (-3,-2)
When we reflect in the line y=k, we use the rule (x, 2k-y)
This implies that:
When we reflect in the line x=k, we use the rule
Now we have x=1
This implies that:
Answer:
110
Step-by-step explanation:
Well, it could be
y+x
10+100
= 110
