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Bad White [126]
2 years ago
11

3 Which of the following relations represent functions? 3 X 2 8 14 22 7 11 11 11 N co ON 7 11 8 N2 11​

Mathematics
1 answer:
ratelena [41]2 years ago
8 0

Answer:

X and W, as they're the only ones that don't repeat an X value.

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Find the mean,median,mode and range for each set of data its 23,27,24,26,26,24,26,24
lilavasa [31]

Mean is the average of the data set, which is found by adding all values together and then dividing that sum by the number of data values.

Median is the middle number of the data set, and can be found by ordering the values from least to greatest. If there are two middle numbers, the average of the two would be the median.

Mode is the number that shows up most frequently in the data set.

Range is found by subtracting the lowest number from the highest number in the data set.

<u>Set 1</u>

Mean:

18+20+22+11+19+18+18=126

126÷7=18

Median:

11, 18, 18, 18, 19, 20, 22 →  18

Mode: 18

Range: 22-11=11

<u>Set 2</u>

Mean: 23+27+24+26+26+24+26+24=200

200÷8=25

Median:

23, 24, 24, 24, 26, 26, 26, 27 → 24+26=50 → 50÷2=25

Mode: 24 and 26

Range: 27-23=4

4 0
3 years ago
Read 2 more answers
Which set of numbers is the most reasonable to describe a person’s hat size? A: Integers. B: Whole numbers. C: Irrational number
FinnZ [79.3K]
The answer is a. integers

8 0
3 years ago
Read 2 more answers
It is not B so plz help me
11111nata11111 [884]

Answer:

The picture is blocked out D:

Step-by-step explanation:

6 0
3 years ago
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Find an equation for the line with slope m through the point (a,c).
lidiya [134]
If you want the answer in point slope form then,

y-y1 = m(x-x1)
y-c = m(x-a)

---------------------------------------

If you want the answer in slope intercept form, then solve for y

y-c = m(x-a)
y-c = mx-ma
y-c+c = mx-ma+c
y = mx-ma+c
y = mx+c-ma
y = mx+(c-ma)

For this answer in slope intercept form the slope is m and the y intercept is c-ma

---------------------------------------

If you want the answer in standard form, then get the variable terms to the left side. Have the constant terms on the right side.

y = mx+c-ma
y-mx = mx+c-ma-mx
-mx+y = c-ma

Optionally you can multiply both sides by -1 to get mx-y = -c+ma but it will depend on your book if this step is carried out or not.

4 0
3 years ago
The semicircle shown at left has center X and diameter W Z. The radius XY of the semicircle has length 2. The chord Y Z has leng
gladu [14]

{\bold{\red{\huge{\mathbb{QUESTION}}}}}

The semicircle shown at left has center X and diameter W Z. The radius XY of the semicircle has length 2. The chord Y Z has length 2. What is the area of the shaded sector formed by obtuse angle WXY?

\bold{ \red{\star{\blue{GIVEN }}}}

RADIUS = 2

CHORD = 2

RADIUS --> XY , XZ , WX

( BEZ THEY TOUCH CIRCUMFERENCE OF THE CIRCLES AFTER STARTING FROM CENTRE OF THE CIRCLE)

\bold{\blue{\star{\red{TO \:  \: FIND}}}}

THE AREA OF THE SHADED SECTOR FORMED BY OBTUSE ANGLE WXY.

\bold{  \green{ \star{ \orange{FORMULA \:  USED}}}}

AREA COVERED BY THE ANGLE IN A SEMI SPHERE

AREA = ANGLE   \: \: IN  \: \:  RADIAN  \times RADIUS

\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}

Total Area Of The Semi Sphere:-

AREA =   \pi \times radius  \\  \\ AREA = \pi \times 2 = 2\pi

Area Under Unshaded Part .

Given a triangle with each side 2 units.

This proves that it's is a equilateral triangle which means it's all angles r of 60° or π/3 Radian

So AREA :-

AREA =  \frac{\pi}{3}  \times radius \\  \\ AREA =  \frac{\pi}{3}  \times 2 \\  \\ AREA =  \frac{2\pi}{3}

\green{Now:- } \\  \green{ \: Area  \: Under \:  Unshaded \:  Part }

Total Area - Area Under Unshaded Part

Area= 2\pi -  \frac{2\pi}{3}  \\ Area =  \frac{6\pi - 2\pi}{3}   \\ Area =  \frac{4\pi}{3}  \:  \: ans

\red \star{Thanks \:  And  \: Brainlist}  \blue\star \\  \green\star  If \:  U  \: Liked \:  My  \: Answer \purple \star

5 0
3 years ago
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