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gtnhenbr [62]
4 years ago
8

Of 350 students polled, some have a cat, some have a dog, and some have both. One hundred seventy-five students have a cat and 1

40 have both types of pets. How many students have a dog only? Explain.
I believe the answer was:
175; Since 175 have a cat or a cat and dog, then the number that have a dog only is 350 − 175 = 175.

But I just needed to check
Mathematics
1 answer:
BigorU [14]4 years ago
6 0
Total students 350
350- 175 cats= 175
175 - 140 both pets = 35 dog only students

I guess
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Find the locus of a point P such that its ordinate is equal to the abscissa. Hence required equation of the locus of point P is y = 5x + 9. Hence required equation of the locus of point P is x = 2y + 3.
3 0
3 years ago
New York City is the most expensive city in the United States for lodging. The mean hotel room rate is $204 per night (USA Today
Ierofanga [76]

Answer:

a) We can find the z score for the value of 225 and we got:

z = \frac{225-204}{55}=0.382

And we can find this probability with the complement rule:

P(z>0.382)=1-P(z

b) z = \frac{140-204}{55}=-1.164

And we can find this probability using the normal standard table or excel and we got:

P(z

c) P(200

And we can find this probability with this difference:

P(-0.072

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.  

P(-0.072

d) For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.2   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.8 of the area on the left and 0.2 of the area on the right it's z=0.842. On this case P(Z<0.842)=0.8 and P(z>0.842)=0.2

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=0.842

And if we solve for a we got

a=204 +0.842*55=250.31

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the costs of a population, and for this case we know the distribution for X is given by:

X \sim N(204,55)  

Where \mu=204 and \sigma=55

We are interested on this probability

P(X>225)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

We can find the z score for the value of 225 and we got:

z = \frac{225-204}{55}=0.382

And we can find this probability with the complement rule:

P(z>0.382)=1-P(z

Part b

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

z = \frac{140-204}{55}=-1.164

And we can find this probability using the normal standard table or excel and we got:

P(z

Part c

P(200

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(200

And we can find this probability with this difference:

P(-0.072

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.  

P(-0.072

Part d

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.2   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.8 of the area on the left and 0.2 of the area on the right it's z=0.842. On this case P(Z<0.842)=0.8 and P(z>0.842)=0.2

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=0.842

And if we solve for a we got

a=204 +0.842*55=250.31

5 0
4 years ago
X/2=4/8 wut?;-; i dont get ittttt :/
Alexandra [31]
Here
Pls mark brainliest

6 0
3 years ago
Read 2 more answers
I need help please???
alexdok [17]

Answer:

x<29

Step-by-step explanation:

This would be the BEST answer. Hope it helps! ☺

4 0
3 years ago
Help plzzzzzzzzzbsjensbsbabbasb
MAXImum [283]
The first one is 24 the second is 96
7 0
3 years ago
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