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nikklg [1K]
4 years ago
7

Can someone help me I think I'm doing my math wrong

Mathematics
1 answer:
Julli [10]4 years ago
7 0

Answer:

Ay bruv I need to see the answer choices to help

Step-by-step explanation:

You might be interested in
C(x)=2x^3+3x^2-1 find rational zeros
3241004551 [841]

Answer:

1/2

Step-by-step explanation:

The Rational Root Theorem says that any rational root has

1. a numerator that is a factor of the constant term

2. a denominator that is a factor of the leading coefficient (that's attached to the highest-power term)

Numerator:  \pm 1

Denominator: \pm 2

That means there are only two possible rational roots: \pm \frac{1}{2}

Try them both by plugging them into the polynomial.

2\left(\frac{1}{2}\right)^3 + 3\left(\frac{1}{2}\right)^2 -1= \frac{1}{4}+\frac{3}{4}-1 =0

Aha!  The negative one-half value does not produce 0

3 0
3 years ago
Please help ASAP!!!!
ryzh [129]
Never seen this type of question but the bottom (4th last answer) makes the most sense
6 0
4 years ago
!GIVING BRAINLIEST!
sweet [91]

Answer:

4.05+4.05+12.9=21

Step-by-step explanation:

Take 21 subtract 12.9 first, then you take the leftover number which is 8.1 then divide it by 2 giving you 4.05.

6 0
3 years ago
Read 2 more answers
How do you solve 4/5= -2/9?
KiRa [710]

Answer:

False

Step-by-step explanation:

The left side 0.8 does not equal to the right side -0.22, which means the given statement is false. Thank you and have a good day. Judging by this question, I presume that you are doing homework or classwork, and I wish you good luck.

3 0
3 years ago
The intercept not graph of 9x^2-4y^2=1
Arte-miy333 [17]
Hello,

(x/(1/3))²-(y/(1/2))²=1 is an hyperbola.

y=0==>x=1/3 or x=-1/3 (-1/3,0) and (1/3,0) are x -intercepts
There are no reals y-intercepts.[(0,-i/2) and (0,i/2)]



5 0
4 years ago
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