If its a parent then the answer would be 60
Answer: 29.28 years
Explanation:
From Kepler's third law the square of orbital period of revolving celestial body is proportional to the cube of semi -major axis from the body it is revolving about.
P² =A³
Where, P is the orbital period in years and A is the semi-major axis in AU (Astronomical units)
It is given that, For Saturn, A = 9.5 AU. We need to find P
⇒P² = (9.5 AU)³
⇒P² = 857.38
⇒P = 29.28 years
Thus, the orbital period of Jupiter is 29.28 years around the Sun.
Answer: the answer is 521
Step-by-step explanation: i don't know how i got that i am a human calculator :)
Ok so standard form is a bit tricky, but I’ll help explain
Here’s and example:
If you have 2x+5y=10 here is how you would solve it
First you divide the x value by what the number is equal to (in our example, 10), and then we get 10/2 is 5. So now we know that
x is equal to five
Keep that in mind. Now we just have to do the same thing for the y value. 5/10 is 2, so you know that
y is equal to two
NOW you put those two together, and graph on the intercepts (the positions on the y and x axis where the lines intercept)
You would put a line on the x axis at 5, and on the y axis at 2
If you have any questions, you can ask
