The two numbers are (5+ √(129))/2 and (5-√(129))/2.
(5+ √(129))/2+ (5-√(129))/2= 5
(5+ √(129))/2* (5-√(129))/2= -26
Hope this helps~
The graphed function, F(x), has a value greater than 0 over the intervals (-0.7, 0.76) and (0.76, ∞) . F(x) > 0 over the intervals (-0.7, 0.76) and (0.76, ∞) is the correct statement [Fourth choice].
About a Graphed Function
The function graph of an object F stands for the set of all points in the plane that are (x, f(x)). The graph of f is also known as the graph of y = f. (x). The graph of an equation is thus a specific example of the graph of a function. A graphed function is a function that has been drawn out on a graph.
It is evident from the attached graph that the supplied function exceeds 0 for the following range:
-0.7 < F(x) < 0.76
And, 0.76 < F(x) < ∞
As a result, the intervals for which the given graphed function, F(x) is greater than 0 are as follows,
(-0.7, 0.76) and (0.76, ∞)
Learn more about a graphed function here:
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Answer:
x = 181 and y = 97
Step-by-step explanation:
let called the first number is x
the second number would be called y
We are given that:
x + y = 278 (1)
x = y + 84 (2)
Let change x in (2) into (1):
y + 84 + y = 278
2y + 84 = 278
Subtract 84 from both side, we got:
2y + 84 - 84 = 278 - 84
2y + 0 = 194
Divide both side by 2, we got:
2y / 2 = 194 / 2
y = 97
Because y = 97 and x + y = 278 so x would equal:
x + 97 = 278
Subtract 97 from both side, we got:
x + 97 - 97 = 278 - 97
x + 0 = 181
x = 181 and y = 97
Hope this helped :3
X = 47 + 9y
xy = 1860
y(47 + 9y) = 1860
47y + 9y² = 1860
9y² + 47y - 1860 = 0
> using a quadratic equation solver on a calculator but you can also use the quadratic equation = [-b+/- √(b²-4ac)]/(2a)
> only integer solution is x = 12
12y = 1860
y = 155
integers are 12 and 155