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zysi [14]
2 years ago
14

when is the appropriate to model data with a linear function. give example of a real world data that can modeled with a linear f

unction include the linear function example of the data
Mathematics
1 answer:
Natalija [7]2 years ago
6 0

Answer:

You can model a data using a linear function when the dependent variable is a multiple of the independent formula plus another constant by the y-intercept. The constant multiple is represented by the slope. In real life problems, linear function is applied when you want to determine the cost given with a slope which is represented by cost per unit time. For example, the cost of wifi connection is $10/month plus $2 inclusive for phone charges. The linear function would be:

C = 10t + 2

where C is the cost and t is time in months

Step-by-step explanation:

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8 0
2 years ago
Evaluate X + Y when X = 13.1 and Y = 2.2<br> A. 10.9<br> B. -10.9<br> C. 35.1<br> D. 15.3
bazaltina [42]
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3 years ago
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Lorico [155]
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5 0
2 years ago
Set D is the set of positive two-digit even numbers less than 25 that do not contain the digit 0.
gavmur [86]

The required set of positive two-digit even numbers less than 25 that do not contain the digit 0 is 12,14,16,18,22,24.

<h3>What is integer?</h3>

An integer is a whole number (not a fractional number) that can be positive, negative, or zero. Zero is not a fraction or decimal of any number. It is neither positive nor negative.

Given:

Set D is the set of positive two-digit even numbers less than 25 that do not contain the digit 0.

According to given question we have

2-digit numbers are the numbers that have two digits and they start from the number 10 and end on the number 99.

Starting at 12 going up the two digit numbers even numbers less than 25 that do not contain the digit 0.

12,14,16,18,22,24

Therefore, the required set of positive two-digit even numbers less than 25 that do not contain the digit 0 is 12,14,16,18,22,24.

Learn more details about integer here:

brainly.com/question/15276410

#SPJ1

4 0
1 year ago
If the coordinates of the endpoints of a diameter of the circle are​ known, the equation of a circle can be found.​ First, find
Evgesh-ka [11]

Answer:

The equation of the circle is (x+3)^2+(y-5)^2 = 17

Step-by-step explanation:

The complete question is

If the coordinates of the endpoints of a diameter of the circle are​ known, the equation of a circle can be found.​ First, find the midpoint of the​ diameter, which is the center of the circle. Then find the​ radius, which is the distance from the center to either endpoint of the diameter. Finally use the​ center-radius form to find the equation.

Find the center-radius  form of the circle having the points (1,4) and (-7,6) as the endpoints of a diameter.

Consider that, if both points are the endpoints of a diameter, the center of the circle is the point that is exactly in the middle of the two points (that is, the point whose distance to each point is equal). Given points (a,b) and (c,d), by using the distance formula, you can check that the middle point is the average of the coordinates. Hence, the center of the circle is given by

(\frac{1-7}{2}, \frac{4+6}{2}) = (-3,5).

We will find the radius. Recall that the radius of the circle is the distance from one point of the circle to the center. Recall that the distance between points (a,b) and (c,d) is given by \sqrt[]{(a-c)^2+(b-d)^2}. So, let us use (1,4) to calculate the radius.

r = \sqrt[]{(1-(-3))^2+(4-5)^2} = \sqrt[]{17}.

REcall that given a point (x_0,y_0). The equation of a circle centered at the point (x_0,y_0) is

(x-x_0)^2+(y-y_0)^2 = r^2

In our case, (x_0,y_0)=(-3,5) and r=\sqrt[]{17}. Then, the equation is

(x-(-3))^2+(y-5)^2 = (x+3)^2+(y-5)^2 = 17

4 0
3 years ago
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