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sweet [91]
3 years ago
15

A dominant gene (W) produces wire-haired texture in dogs; its recessive allele (w) produces smooth hair. A group of heterozygous

wire-haired individuals are crossed and their F1 progeny are then test-crossed. Determine the expected genotypic and phenotypic ratios among the test cross progeny:
Biology
1 answer:
Marysya12 [62]3 years ago
8 0

Answer: Phenotypic ratio=2:2; Genotypic ratio= 2:2.

Explanation: Test cross is the breeding of an individual with Phenotypically recessive individuals.

Heterozygous wire-haired = Ww

Recessive trait= ww

Test crossing result of offspring= Ww Ww ww ww

Genotypic ratio (genetic composition) = 2:2

Phenotypic ratio= 2:2

2 offsprings are wire-haired and 2 Offspring are smooth-haired.

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Answer:

The missing step is oxygen is removed from the water after step 3.

Explanation:

The steps listed by Xavier are:

  1. <em>Water is drawn in trough pores and enters the central cavity. </em>
  2. <em>Food is filtered and digested. </em>
  3. <em>Water leaves trough an opening at the top of the body.</em>

Porifera or sponges are aquatic, immobile invertebrates whose structure is saccular with an upper opening, the osculus.

Sponges absorb water through their pores, where the porocytes are found, and through flagellated cells -the coanocytes- the movement that allows the entrance of water to the spongocele or atrium is produced, in addition to the phagocytosis of organic elements.

Once the water is in the interior chamber of the sponges, the organic particles are phagocyted to be digested, and the oxygen is removed from the water, and passes through diffusion into the cell.  The waste products, as well as carbon dioxide, are released into the water that will be expelled through the osculus.

<u><em>In Xavier's list, the missing step is the removal of oxygen from the water, before it is expelled from the body of the sponge</em></u><em>.</em>

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Learn more:

Sponge structure brainly.com/question/11256747

6 0
4 years ago
MULTIPLE CHOICE
adoni [48]

Answer:

B

Explanation:

Its 23 in mitosis cell division

8 0
3 years ago
During the process of ________, an existing tissue is replaced by bone.
Pachacha [2.7K]
During the process of ossification, an existing tissue is replaced by bone.
6 0
3 years ago
A recessive allele causes phenylketonuria (PKU) when homozygote. If the frequency of the recessive allele is 0.05 in the populat
Radda [10]

Answer:

0.095

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Phenylkentonuria is a disease caused by a recessive allele.

The frequency of the recessive allele + the frequency of the dominant allele equals 1.

The frequency of the recessive allele is q = 0.05

The frequency of the dominant allele then is p = 1  - q = 0.95

If people mate randomly, the frequency of the homozygous dominant genotype will be p², the frequency of the heterozygous genotype will be 2pq and the frequency of the homozygous recessive genotype will be q² .

2pq=2× 0.05 × 0.95

2pq=0.095

The heterozygote frequency in the population is 0.095

4 0
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The essence of meiosis is that a. specialized cell division reduces the chromosome number by half b. gametes are formed that are
marishachu [46]

Answer:

e. a and d are correct

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