Answer is: molar mass of sodium iodide is 149.89424 g/mol.
Chemical reaction: Na⁺ + I⁻ → NaI.
The molar mass (M)<span> is the </span>mass<span> of a given substance (in this example sodium iodide</span><span>) divided by the </span>amount of substance<span>.
</span>M(NaI) = Ar(Na) + Ar(I) · g/mol.
M(NaI) = 22.98977 + 126.90447 · g/mol.
M(NaI) = 149.89424 g/mol.
Answer:
71.372 g or 0.7 moles
Explanation:
We are given;
- Moles of Aluminium is 1.40 mol
- Moles of Oxygen 1.35 mol
We are required to determine the theoretical yield of Aluminium oxide
The equation for the reaction between Aluminium and Oxygen is given by;
4Al(s) + 3O₂(g) → 2Al₂O₃(s)
From the equation 4 moles Al reacts with 3 moles of oxygen to yield 2 moles of Aluminium oxide.
Therefore;
1.4 moles of Al will require 1.05 moles (1.4 × 3/4) of oxygen
1.35 moles of Oxygen will require 1.8 moles (1.35 × 4/3) of Aluminium
Therefore, Aluminium is the rate limiting reagent in the reaction while Oxygen is the excess reactant.
4 moles of aluminium reacts to generate 2 moles aluminium oxide.
Therefore;
Mole ratio Al : Al₂O₃ is 4 : 2
Thus;
Moles of Al₂O₃ = Moles of Al × 0.5
= 1.4 moles × 0.5
= 0.7 moles
But; 1 mole of Al₂O₃ = 101.96 g/mol
Thus;
Theoretical mass of Al₂O₃ = 0.7 moles × 101.96 g/mol
= 71.372 g
Question 1: Fission
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Answer:C. distillation
Explanation:
Compounds having different boiling points when mixed can be separated by Fractional distillation.
Now when there is a mixture of water and alcohol, Upon heat, we would see that the alcohol will boil at a lower temperature than water for eg, ethanol will boil at 78.5 degrees Celsius, vaporizes and distills into the fractionating columns leaving the water which we know boils at 100 degrees Celsius.
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