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Eva8 [605]
3 years ago
5

What is the heat of vaporization of water?

Chemistry
1 answer:
andrew11 [14]3 years ago
7 0
The molecules in liquid water are held together by relatively strong hydrogen bonds and its enthalpy of vaporization, 40.65 kJ/mol is more than five times the energy required to heat the same quantity of water from: 0 °C to 100 °C (cp = 75.3 J K−1 mol−1).

Hope this helps.
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5 points<br> What is the name of the atom pictured here? Use a periodic table if<br> needed. *
photoshop1234 [79]

Answer:

There is nothing attached to this question so I unfortunately cannot help you

Explanation:

3 0
3 years ago
Basic Stoichiometry
MrMuchimi

Answer:

1. 23.3 g

2. 82 g

3. 0.402 mol

4. 0.506 mol

Explanation:

We can convert moles (n) to mass (m) using the following expressions that include the molar mass (M).

n = m/M

m = n × M

1. The molar mass of NH₄Cl is 53.49 g/mol.

m = 0.436 mol × 53.49 g/mol = 23.3 g

2. The molar mass of Ca(NO₃)₂ is 164.09 g/mol.

m = 0.50 mol × 164.09 g/mol = 82 g

3. The molar mass of NaCl is 58.44 g/mol.

n = 23.5 g/(58.44 g/mol) = 0.402 mol

4. The molar mass of KMnO₄ is 158.03 g/mol.

n = 79.9 g/(158.03 g/mol) = 0.506 mol

6 0
3 years ago
Write the chemical symbol for an element in Period 6 and Group 2A
Nataly_w [17]
The answer is Ba (56)
3 0
4 years ago
Loren is examining a hair found at a crime scene. He notes radical changes in the coloring of the hair. What is the term for thi
nordsb [41]

Answer:

Granules of the hair cortex.

Explanation:

<h2>hope it helpfully...</h2>
4 0
3 years ago
Read 2 more answers
Which sample contains the greater number of atoms, a sample of Li that contains 6.8 x 10^22 atoms or a 1.97 mole sample of Na?
IrinaVladis [17]

Answer:

                     1.97 moles of Na contains greater number of atoms than 6.8 × 10²² atoms of Li.

Explanation:

                    To solve this problem we will first calculate the number of atoms contained by 1.97 moles of Na and then will compare it with 6.8 × 10²² atoms of Li.

                    As we know that 1 mole of any substance contains exactly 6.022 × 10²³ particles which is also called as Avogadro's Number. So in order to calculate the number of atoms contained by 1.97 moles of Na, we will use following relation,

          Moles  =  Number of Atoms ÷ 6.022 × 10²³ atoms.mol⁻¹

Solving for Number of Atoms,

          Number of Atoms  =  Moles × 6.022 × 10²³ Atoms.mol⁻¹

Putting values,

          Number of Atoms  =  1.07 mol × 6.022 × 10²³ Atoms.mol⁻¹

          Number of Atoms  = 1.18 × 10²⁴ Atoms of Na

Hence,

          1.97 moles of Na contains greater number of atoms than 6.8 × 10²² atoms of Li.

4 0
3 years ago
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