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Nataly_w [17]
3 years ago
11

Find the area of trapezoids. Please!!!!!!!!!!

Mathematics
2 answers:
bogdanovich [222]3 years ago
6 0

Check the picture below.

\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} a,b=\stackrel{bases}{parallel~sides}\\ h=height \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{left-side trapezoid}}{ \begin{cases} a=2\\ b=5\\ h=3 \end{cases}}\implies A=\cfrac{3(2+5)}{2}\implies A=\cfrac{21}{2}\implies A=10\frac{1}{2} \\\\\\ \stackrel{\textit{right-side trapezoid}}{ \begin{cases} a=1\\ b=4\\ h=3 \end{cases}}\implies A=\cfrac{3(1+4)}{2}\implies A=\cfrac{15}{2}\implies A=7\frac{1}{2}

bulgar [2K]3 years ago
3 0

Blue is 42 and green is 30

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Answer:

9 < x

Step-by-step explanation:

5x - 47< 3(12x - 108) – 2​

Distribute

5x - 47< 36x - 324 – 2​

Combine like terms

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Subtract 5x from each side

5x-5x - 47< 36x-5x-326

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Add 326 to each side

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Answer:

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Step-by-step explanation:

Let,  D=\frac{d}{dx}

Now, us simplify the given differential equation and write it in terms of D,

36y''-48y'-48y=0

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Applying the boundary conditions, we get,

A+B=1

2A-\frac{2}{3}B=0

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A=\frac{1}{4} ,B=\frac{3}{4}

Hence,

y=\frac{1}{4} e^{2x}+\frac{3}{4} e^{-\frac{2}{3}x }

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