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Rom4ik [11]
3 years ago
14

How many integers n satisfy the inequality 3n² - 4≤44?

Mathematics
1 answer:
Margaret [11]3 years ago
7 0

Answer:

The possible values of n  for n ≤ +4  =  (-∞,+4]

The possible values of n for  n ≤ -4  =  (-∞,-4]

Step-by-step explanation:

Here, the given inequality is:

3n^2 - 4 \leq 44

Firstly, let us solve the given inequality for the desirable value of n.

3n^2 - 4 \leq 44

Adding 4 on both sides, we get:

3n^2 - 4 + 4 \leq 44 + 4

3n^2  \leq 48

or, n^2 \leq \frac{48}{3}\implies n^2 \leq 16\\

⇒   n ≤ +4  or  n ≤ -4

So, the possible values of n  for  n ≤ +4  =  (-∞,+4]

And,  the possible values of n  for  n ≤ -4  =  (-∞,-4]

So, we can pick any of the integer values from the both defined sets.

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The dimensions of a rectangle are shown. What is the area of the rectangle?
ivanzaharov [21]

Answer:

=(3x+8) (5x+2)

=15x2 + 46x + 16 units

8 0
3 years ago
A unit vector lies in the xy plane, at an angle of 153 degrees from the x axis, with a positive y component. What is the unit ve
tino4ka555 [31]

Answer:

unit vector = -0.891i + 0.454j

Step-by-step explanation:

Given that;

magnitude of unit vector =

angle of 153° degrees from the x axis, with a positive y component

{ second quadrant }

so, x and y components of the vector are;

x component = 1 × cos(153°) = - 0.891

y component = 1 × sin(153°) = 0.454

⇒ -0.891i + 0.454j

Therefore, unit vector = -0.891i + 0.454j

3 0
3 years ago
The taxiways and runways of a major airport are carefully monitored to expedite takeoffs and landings and to prevent collisions.
tatyana61 [14]

Answer:

18.04% probability that exactly 3 serious deviations and incursions will occur at LAX in a randomly selected year

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

Suppose the mean number of deviations and incursions per year at the Los Angeles International Airport (LAX) is 2.

This means that \mu = 2

Find the probability that exactly 3 serious deviations and incursions will occur at LAX in a randomly selected year

This is P(X = 3).

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 3) = \frac{e^{-2}*2^{3}}{(3)!} = 0.1804

18.04% probability that exactly 3 serious deviations and incursions will occur at LAX in a randomly selected year

4 0
3 years ago
Can someone help me really fast?​
pshichka [43]
3? I pretty sure it’s three sorry if I’m wrong
3 0
3 years ago
Can you check if I did this right? (:
ra1l [238]
The graph looks accurate make sure you create a table of values and clearly dot the points at (0,-3) and (2,-3).
7 0
3 years ago
Read 2 more answers
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