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zavuch27 [327]
3 years ago
13

When a ball rolls down an inclined plane, it gains speed because of gravity. When rolling up, it loses speed because of gravity.

Physics
1 answer:
Greeley [361]3 years ago
5 0

Answer:

Because the path of the ball is perpendicular to the gravitational force.

Explanation:

In the first case, trajectory of the ball has a component parallel to gravity. Therefore, gravity speeds up the ball.

In the second case, trajectory of the ball has a component anti-parallel to gravity. Therefore, gravity slows down the ball.

When ball rolls on the horizontal surface, the trajectory of the ball is perpendicular to the gravitational force. Therefore, gravity doesn’t play any role.

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A 30 kg box sits on the floor it requires 275N of force to get it moving once it is moving it only takes 225N of force.what are
gavmur [86]

1) The coefficient of static friction is 0.935

2) The coefficient of kinetic friction is 0.765

Explanation:

1)

When a force is applied on a box sitting on the floor, the force that must be applied in order to make the box moving is equal to the maximum force of static friction between the floor and the box, which is:

F = \mu_s mg

where

\mu_s is the coefficient of static friction

m is the mass of the box

g is the acceleration of gravity

Here we have:

m = 30 kg

g=9.8 m/s^2

F = 275 N

Therefore, the coefficient of static friction is

\mu_s = \frac{F}{mg}=\frac{275}{(30)(9.8)}=0.935

2)

Once the box is in motion, the force that must be applied in order to make the box moving at constant velocity is equal to the force of kinetic friction between the floor and the box, which is:

F = \mu_k mg

where

\mu_k is the coefficient of kinetic friction

m is the mass of the box

g is the acceleration of gravity

Here we have:

m = 30 kg

g=9.8 m/s^2

F = 225 N

Therefore, the coefficient of kinetic friction is

\mu_k = \frac{F}{mg}=\frac{225}{(30)(9.8)}=0.765

Learn more about friction:

brainly.com/question/6217246

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#LearnwithBrainly

8 0
3 years ago
Can a vector be shorter than one of its components
Sauron [17]
It can never be shorter than a component - magnitude of avector is the square root of the sum of the components squared, and a square function never produces a negative number. However, it can be the same size as its component, if that component is the only one
3 0
4 years ago
Stacey runs around a 400 meter track 2 times in 5 minutes. How does her displacement differ from her distance? *
liq [111]

Answer:

Distance is 800 m and Displacement is 0 m

Explanation:

Total Distance

= 400(2)

= <u>800</u><u> </u><u>m</u>

Total Displacement

= <u>0</u><u> </u><u>m</u> since she returns to the same spot

6 0
3 years ago
Suppose the electric field in some region is found to be E = kr3 ˆr, in spherical coordinates (k is some constant). (a) Find the
Assoli18 [71]

Answer:

Part a)

\rho = 3\epsilon_0 k r^2

Part b)

Q = 4\pi \epsilon_0kR^5

Explanation:

Part a)

As we know that electric field intensity due to some given charge distribution is given as

E = kr^3 \hat r

now electric flux through a spherical surface of radius r is given as

\phi = E. A

\phi = kr^3(4\pi r^2)

now by Guass law we know that

E.A = \frac{q}{\epsilon_0}

q = 4\pi \epsilon_0kr^5

now volume charge density is given as

\rho = \frac{q}{\frac{4}{3}\pi r^3}

\rho = 3\epsilon_0 k r^2

Part b)

Total charge inside the radius R is given as

Q = 4\pi \epsilon_0kR^5

7 0
3 years ago
Beats: A policeman in a stationary car measures the speed of approaching cars by means of an ultrasonic device that emits a soun
e-lub [12.9K]

Answer:

The frequency of the beats is 43.6408 kHz

Explanation:

Given:

f = frequency = 39.6 kHz

vc = speed of the car = 35 m/s

vs = speed of the sound = 343 m/s

Question: What is the frequency of the beats, f' = ?

As the car moves towards the source, the frequency of the beats

f'=f*(1+\frac{v_{c} }{v_{s} } )=39.6*(1+\frac{35}{343} )=43.6408kHz

4 0
3 years ago
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