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3 years ago

What velocity must a car with a mass of 1280 kg have in order to have the same momentum as a 2230?

1 answer:

8 0

Momentum = (mv).
<span>(2110 x 24) = 50,640kg/m/sec. truck momentum. </span>
<span>Velocity required for car of 1330kg to equal = (50,640/1330), = 38m/sec</span>

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5. A family leaves for an evening walk around the neighborhood. They leave at 5 pm and return at 6 pm. They traveled a total of

vlabodo [156]

This question involves the concepts of average speed, distance, and time.

The average speed of the family is "2.5 mi/hr".

<h3>AVERAGE SPEED</h3>

The average speed is defined as the ratio of the total distance covered with the total time taken to cover it.

$v=\frac{s}{t}$

where,

s = distance covered = 2.5 miles
t = total time taken = 1 hour
v = average speed = ?

Therefore,

$v=\frac{2.5\ mi}{1\ hr}$

v = 2.5 mi/hr

Learn more about average speed here:

brainly.com/question/12322912

4 0

2 years ago

A ball is dropped from rest. how fast is the ball going after 3 seconds

Airida [17]

Answer:

v = 29.4m/s

Explanation:

Since the ball is dropped at rest,

u = 0m/s

a = 9.81m/s²

Using

v = u + at

After 3 seconds,

v = 0 + (9.81)(3)

v = 29.4m/s

5 0

3 years ago

2.)

Oduvanchick [21]

Answer:

$-22.7 m/s^2$

Explanation:

This is a uniformly accelerated motion, so we can determine the deceleration of the car by using a suvat equation:

$v^2-u^2=2as$

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance covered

For the car in this problem,

u = 27.8 m/s

v = 0

s = 17 m

Solving for a, we find the acceleration:

$a=\frac{v^2-u^2}{2s}=\frac{0-27.8^2}{2(17)}=-22.7 m/s^2$

4 0

3 years ago

If your car runs out of gas and you must push it 250 m to the nearest gas station. How much work is done on the car if it is pus

tankabanditka [31]

Answer:

1750 Joules.

Explanation:

Work done = force * distance

= 7 * 250

= 1750 Joules.

6 0

2 years ago

A firecracker breaks up into three pieces, one of which has a mass of 200 g and flies off along the x-axis with a speed of 82.0

Mamont248 [21]

Answer:

$|P_3|=21.242m/s$

Explanation:

From the question we are told that:

Mass $m=200g=0.2$

Speed $v=82.0m/s$

Mass $M_2=300g=0.3kg$

Speed $V_2=45.0m/s$

Generally the equation for Magnitude of the Third piece is mathematically given by

$P_1+P_2+P_3=0$

$|P_3|=|P_1+P_2|$

Where

$P_1=m_1v_1$

$P_1=0.2*82$

$P_1=16.4kgm/s$

And

$P_2=0.3*45$

$P_2=13.5kgm/s$

Therefore

$|P_3|=\sqrt{16.4^2+13.5^2}$

$|P_3|=21.242m/s$

8 0

3 years ago